Ruby Yaml序列化问题

Question

关于序列化的奇怪问题，可能是我做错了什么，但不确定是什么。

提前感谢你的帮助。

输入yaml文档

---
ssl_user_clients:
  - first_name: donnald
    surname: duck
    email: donnald.duck@acme.corp
    country: fantasyland
    state: desert
    locality: Disney
    org_name: Acme corp

预期的yaml文档

---
ssl_user_clients:
  - first_name: donnald
    surname: duck
    password: k)NzzC+&Dg?-RY|0
    email: donnald.duck@acme.corp
    country: fantasyland
    state: desert
    locality: Disney
    org_name: Acme corp

我的代码出现了奇怪的结果：

---
ssl_user_clients:
- &1
  first_name: donnald
  surname: duck
  email: donnald.duck@acme.corp
  country: fantasyland
  state: desert
  locality: Disney
  org_name: Acme corp
*1:
  first_name: donnald
  surname: duck
  email: donnald.duck@acme.corp
  country: fantasyland
  state: desert
  locality: Disney
  org_name: Acme corp
  password: k)NzzC+&Dg?-RY|0

我的Ruby代码：

#!/usr/bin/env ruby

require "yaml"

def generate_activation_code(size = 16)
  charset = %w{0 1 2 3 4 6 7 9 A C D E F G H J K M N P Q R T V W X Y Z a b c d e f g h i j k m n o p q r s t u v w x y z ! @ $ % ^ & * ( ) _ ? ~ + - = / \ | < > { } [ ]}
  (0...size).map{ charset.to_a[rand(charset.size)] }.join
end


def get_cleaned_password
    password = generate_activation_code
    password.split().collect{|x| x.strip}.join()
end


hash = YAML.load(File.read(ARGV[0]))

puts "Hash from file"
puts hash
puts
puts


for user in hash["ssl_user_clients"]
    if not user["password"]
        new_password = get_cleaned_password
    end

    pass = { "password" => new_password }
    hash[user] = user.merge pass
end


puts hash.to_yaml

open(ARGV[0], File::TRUNC) {}
File.open(ARGV[0], 'w') {|f| f.write hash.to_yaml( :Indent => 4, :UseHeader => true, :UseVersion => true ) }

请有人协助这一点，因为这让我困惑，我真的没有想到会看到这一点。

一些调试信息。

Hash from file
{"ssl_user_clients"=>[{"first_name"=>"donnald", "surname"=>"duck", "email"=>"donnald.duck@acme.corp", "country"=>"fantasyland", "state"=>"desert", "locality"=>"Disney", "org_name"=>"Acme corp"}]}

Hash before hash.to_yaml
{"ssl_user_clients"=>[{"first_name"=>"donnald", 
                        "surname"=>"duck",
                        "email"=>"donnald.duck@acme.corp",       
                        "country"=>"fantasyland", 
                        "state"=>"desert", 
                        "locality"=>"Disney",
                        "org_name"=>"Acme corp"}], 
                      {"first_name"=>"donnald", 
                        "surname"=>"duck", 
                        "email"=>"donnald.duck@acme.corp",
                        "country"=>"fantasyland", 
                        "state"=>"desert", 
                        "locality"=>"Disney", 
                        "org_name"=>"Acme corp"}=>{"first_name"=>"donnald",
                        "surname"=>"duck", 
                        "email"=>"donnald.duck@acme.corp",
                        "country"=>"fantasyland", 
                        "state"=>"desert", 
                        "locality"=>"Disney", 
                        "org_name"=>"Acme corp", 
                        "password"=>"4?zkoff3^hmMC-<7"}}

下面详细介绍的更改修复了yaml的损坏，但是输出有缩进问题。

很棒的东西，这是预期的工作，但是输出有一个缩进问题。

下面修复了根据@infused (谢谢)给出的建议的损坏：

for user in hash["ssl_user_clients"]
    if not user["password"]
        user["password"] = get_cleaned_password
    end
end

按照预期更正输出。

---
ssl_user_clients:
  - first_name: donnald
    surname: duck
    email: donnald.duck@acme.corp
    country: fantasyland
    state: desert
    locality: Disney
    org_name: Acme corp
    password: =)%DoHHpyRrx|?v=

我假设下面的代码可以确保缩进是正确的。

to_yaml( :Indent => 4, :UseHeader => true, :UseVersion => true ) }

Answer 1

您正在破坏for user in hash["ssl_user_clients"]循环中的散列，因为user包含一个散列，并且您正在使用user作为键创建一个新元素。

通过以下方式更新密码：

for user in hash["ssl_user_clients"]
  user['password'] = get_cleaned_password
end

现在，您可以使用puts hash.to_yaml验证，hash将更新每个用户的密码。