将elgg php函数更改为javascript函数

Question

将elgg_get_friendly_time更改为javascript

我输入了这个$params = array('time' => $time);和return elgg_echo("friendlytime:justnow");

<?php

function elgg_get_friendly_time($time) {

// return a time string to short circuit normal time formatting
$params = array('time' => $time);
$result = elgg_trigger_plugin_hook('format', 'friendly:time', $params, NULL);
if ($result) {
return $result;
}

$diff = time() - (int)$time;

$minute = 60;
$hour = $minute * 60;
$day = $hour * 24;

if ($diff < $minute) {
return elgg_echo("friendlytime:justnow");
} else if ($diff < $hour) {
$diff = round($diff / $minute);
if ($diff == 0) {
$diff = 1;
}

if ($diff > 1) {
return elgg_echo("friendlytime:minutes", array($diff));
} else {
return elgg_echo("friendlytime:minutes:singular", array($diff));
}
} else if ($diff < $day) {
$diff = round($diff / $hour);
if ($diff == 0) {
$diff = 1;
}

if ($diff > 1) {
return elgg_echo("friendlytime:hours", array($diff));
} else {
return elgg_echo("friendlytime:hours:singular", array($diff));
}
} else {
$diff = round($diff / $day);
if ($diff == 0) {
$diff = 1;
}

if ($diff > 1) {
return elgg_echo("friendlytime:days", array(diff));
} else {
return elgg_echo("friendlytime:days:singular", array($diff));
}
}
}

?>

Answer 1

我在文档中查找了该函数：

http://reference.elgg.org/engine_2lib_2output_8php.html#aa008ab7b454c680f83ca7a62409c6ab5

它提醒了我，我有一些JS代码可以做类似的事情，这可能会对你有所帮助：

function get_friendly_date(date) {
    var now = new Date();
    var diff = Math.floor((now - date) / 1000); // seconds
    var min = 60;           // seconds
    var hour = 3600;        // seconds
    var day = 86400;        // seconds
    var month = 30.5 * day; // seconds
    months = Math.floor(diff / month);
    if (months >= 1) return months + " months ago";
    else {
        days = Math.floor(diff / day);
        if (days == 1) return days + " day ago";
        else if (days > 1) return days + " days ago";
        else {
            hours = Math.floor(diff / hour);
            if (hours == 1) return hours + " hour ago"
            else if (hours > 1) return hours + " hours ago";
            else {
                mins = Math.floor(diff / min);
                if (mins == 1) return mins + " min ago";
                else if (mins > 1) return mins + " mins ago";
                else {
                    return diff + " seconds ago";
                }
            }
        }
    }
}

我把它放在一把小提琴里，你可以在这里摆弄：

http://jsfiddle.net/hM2LU/

希望这能有所帮助！