我一直在论坛上到处寻找单向的manyToMany查询。我发现了很多例子,但我不能真正地调整它们来满足我的需求:
我有两个实体类(动画和用户)
Anime {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Column(name = "anime_id")
private Integer id;
//Other fields etc.
}
User {
@Id
@ValidUsername
@Column(name = "user_id")
private String username;
@ManyToMany()
@JoinTable(name = "users_animes",
joinColumns = @JoinColumn(name = "anime_id", referencedColumnName = "anime_id"),
inverseJoinColumns = @JoinColumn(name = "user_id", referencedColumnName = "user_id"))
private final List<Anime> animes = new ArrayList<>();
}动漫只是简单地保存来自动漫的数据。用户拥有用户的用户名等,以及他订阅的动漫列表。
现在,我正在尝试查找一个查询,该查询可以让我获得该列表中的所有动画。它在一个表中被映射为"users_animes“。
这将是一个很大的帮助,因为我是JPQL的新手。
谢谢!
发布于 2015-06-25 20:51:46
这里有一个简单的例子。假设我们有Country Entity,它可以有多个can:
@Entity
@Table (name = "countries")
public class Country implements Serializable {
@Id
@Column (name = "coun_id")
@GeneratedValue(strategy = GenerationType.IDENTITY)
private Long id;
@Column (name = "country_name")
private String countryName;
@ManyToMany (cascade = CascadeType.ALL)
@JoinTable (
name = "citizen_country",
joinColumns = @JoinColumn (name = "country_id", referencedColumnName = "coun_id"),
inverseJoinColumns = @JoinColumn (name = "citizen_id", referencedColumnName = "cit_id")
)
private List<Citizen> citizens;
public Country() {}
public Country(String countryName) {
this.countryName = countryName;
}
//getters and setters
}和公民,可以属于多个国家/地区:
@Entity
@Table (name = "citizens")
public class Citizen implements Serializable {
@Id
@Column (name = "cit_id")
@GeneratedValue(strategy = GenerationType.IDENTITY)
private Long id;
@Column (name = "country_name")
private String citizenName;
public Citizen() {}
public Citizen(String citizenName) {
this.citizenName = citizenName;
}
public void setId(Long id) { this.id = id; }
public Long getId() { return id; }
public void setCitizenName(String citizenName) { this.citizenName = citizenName; }
public String getCitizenName() { return citizenName; }
//getters and setters
}它是单向的,正如您所希望的那样。因此,公民实体不知道国家,所以你不能直接获得某个公民属于哪个国家的信息。但是,您可以检索有关哪些公民属于某个国家的信息。
更进一步,您可以填充表:
Citizen citizen1 = new Citizen("Smith");
Citizen citizen2 = new Citizen("Kowalski");
Citizen citizen3 = new Citizen("Muller");
dataAccess.saveCitizen(citizen1);
dataAccess.saveCitizen(citizen2);
dataAccess.saveCitizen(citizen3);
// now let's fetch them from DB, along with their other properties (only id in this case)
citizen1 = dataAccess.getCitizenByName("Smith");
citizen2 = dataAccess.getCitizenByName("Kowalski");
citizen3 = dataAccess.getCitizenByName("Muller");
Country country1 = new Country("Foo");
Country country2 = new Country("Bar");
// create lists to hold citizens for each country
List<Citizen> citizenList1 = new ArrayList();
List<Citizen> citizenList2 = new ArrayList();
// add elements to the lists
citizenList1.add(citizen1);
citizenList1.add(citizen2);
citizenList2.add(citizen2);
citizenList2.add(citizen3);
//assign lists of citizens to each country
country1.setCitizens(citizenList1);
country2.setCitizens(citizenList2);
//save data in DB
dataAccess.saveCountry(country1);
dataAccess.saveCountry(country2);
//fetch list of all persisted countries (associated Citizens will come along)
countries = dataAccess.getAllCountries();最后:
@Stateless
public class DataAccess {
@PersistenceContext
EntityManager em;
public void saveCountry(Country country) {
em.persist(country);
}
public void saveCitizen(Citizen citizen) {
em.persist(citizen);
}
public Citizen getCitizenByName(String name) {
Query query = em.createQuery("SELECT c FROM Citizen c WHERE c.citizenName = :name");
query.setParameter("name", name);
return (Citizen) query.getSingleResult();
}
public List<Country> getAllCountries() {
Query query = em.createQuery("SELECT c FROM Country c");
return (List<Country>) query.getResultList();
}
}https://stackoverflow.com/questions/31048573
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