将一个数组的值与另一个数组的键匹配

Question

PHP newb试图在array1的键中查找array2的值，并在它们匹配的地方对array1的值执行一些操作。我很确定这很容易，但是我对php不是很熟悉。任何帮助都将不胜感激。一直在修补array_search和in_array，但无法让任何东西工作。

希望得到的结果是，在array1的键中找到array2的值时，匹配的键值对的值将除以2。

$array1 = Array ( 
     [shore_anchor] => 0 
     [inter_anchor] => 0 
     [offshore_anchor] => 0 
     [offshore_gear] => 5  
     [shore_infrastructure] => 0  
     [inter_infrastructure] => 0  
     [coastal_vessel] => 5  
     [offshore_vessel] => 5 );
$array2 = Array ( [0] => infrastructure [1] => anchor );

foreach($array2 as $key1 => $val1){
    foreach ($array1 as $key => $value) {
      if ($key1 == $key){
        echo "$key => $value <br />";
  }}}}

Answer 1

我认为这可能是它，但欢迎评论或效率。

$result = array_flip($array2);

foreach($result as $needle => $val1){
    foreach ($array1 as $haystack => $val2) {
        if (strpos($haystack, $needle) !== false) {
            echo "$haystack => $val2\n";
        }
    }
}

Answer 2

一种方法：

<?php
$array1 = Array(
        'shore_anchor'=>0,
        'inter_anchor'=>0,
        'offshore_anchor'=>0,
        'offshore_gear'=>5,
        'shore_infrastructure'=>0,
        'inter_infrastructure'=>0,
        'coastal_vessel'=>5,
        'offshore_vessel'=>5
);

$array2 = Array(
        '0'=>'infrastructure',
        '1'=>'anchor'
);


foreach ($array1 as $key=>$value){
    $x = explode('_',$key);

    if (in_array($x[0],$array2) || in_array($x[1],$array2)){
        echo "$key => $value <br />";
    }
}

// for PHP 5.6.0 +



$match = '#' . implode('|',$array2) . '#';


$x = array_filter($array1,function ($key) use ($match){
    return preg_match($match,$key);
},ARRAY_FILTER_USE_KEY);


foreach ($x as $key=>$value){

    echo "$key => $value <br />";
}