UIButton -在调用触摸重复时防止调用触碰事件

Question

我有一个按钮，行为在一种方式，当用户点击它和另一个当用户双击它。在用户双击按钮的情况下，我不希望发生单击行为。

在识别双击的情况下，如何防止调用触碰事件？

Answer 1

你可以使用Target-action；对于UIControlEvents，你可以像这样使用"UIControlEventTouchDown“和"UIControlEventTouchDownRepeat”：

UIButton * button = [UIButton buttonWithType:UIButtonTypeContactAdd];
button.frame = CGRectMake(150, 200, 50, 50);
[button addTarget:self action:@selector(buttonSingleTap:) forControlEvents:UIControlEventTouchDown];
[button addTarget:self action:@selector(buttonMutipleTap:) forControlEvents:UIControlEventTouchDownRepeat];
[self.view addSubview:button];

- (void)buttonSingleTap:(UIButton *)btn{
    [self performSelector:@selector(buttonAction:) withObject:btn afterDelay:0.5];
}

- (void)buttonAction:(UIButton *)sender{
    NSLog(@"single tap");
}

- (void)buttonMutipleTap:(UIButton *)btn{
    [NSObject cancelPreviousPerformRequestsWithTarget:self selector:@selector(buttonAction:) object:btn];
    NSLog(@"mutiple tap!");
}

但是会有0.5秒的延迟！

Answer 2

据我所知，你想在同一个按钮上有不同的行为，所以只需在下面的代码中应用两个不同的tap gesture.The可能会对你有所帮助。

UIButton *btn1=[[UIButton alloc]init];  //your button

//Two diff method call for two diff behaviour

UITapGestureRecognizer *singleTap = [[UITapGestureRecognizer alloc] initWithTarget:self  action:@selector(singleTapEvent:)];
UITapGestureRecognizer *doubleTap = [[UITapGestureRecognizer alloc] initWithTarget:self  action:@selector(doubleTapEvent:)];

//specify the number of tapping event require to execute code.
singleTap.numberOfTapsRequired = 1;  
doubleTap.numberOfTapsRequired = 2;

[singleTap requireGestureRecognizerToFail:DoubleTap];

//Apply  multiple tap gesture to your  button
[btn1 addGestureRecognizer:singleTap]; 
[btn1 addGestureRecognizer:doubleTap];