我正在尝试获取几个SQL请求的交集。我尝试了很多命令,但还是卡住了。
以下是3个请求。
有谁有办法帮我吗?
1
SELECT username
FROM mdl_user
INNER JOIN mdl_quiz_grades
ON mdl_user.id=mdl_quiz_grades.userid
WHERE mdl_quiz_grades.quiz = 17;2
SELECT username
FROM mdl_user
INNER JOIN mdl_quiz_grades
ON mdl_user.id=mdl_quiz_grades.userid
WHERE mdl_quiz_grades.quiz = 16;3.
SELECT username
FROM mdl_user
INNER JOIN mdl_quiz_grades
ON mdl_user.id=mdl_quiz_grades.userid
WHERE mdl_quiz_grades.quiz = 15;发布于 2015-05-20 17:08:36
可以使用Joins轻松重写INTERSECT:
SELECT t1.username
from
(
SELECT username
FROM mdl_user
INNER JOIN mdl_quiz_grades
ON mdl_user.id=mdl_quiz_grades.userid
WHERE mdl_quiz_grades.quiz = 17
) as t1
join
(
SELECT username
FROM mdl_user
INNER JOIN mdl_quiz_grades
ON mdl_user.id=mdl_quiz_grades.userid
WHERE mdl_quiz_grades.quiz = 16
) as t
on t1.username = t2.username
join
(
SELECT username
FROM mdl_user
INNER JOIN mdl_quiz_grades
ON mdl_user.id=mdl_quiz_grades.userid
WHERE mdl_quiz_grades.quiz = 15
) as t3
on t1.username = t3.username但是在您的例子中,它是几乎相同的查询,只是不同的WHERE条件。您可以应用聚合逻辑:
SELECT username
FROM mdl_user
INNER JOIN mdl_quiz_grades
ON mdl_user.id=mdl_quiz_grades.userid
WHERE mdl_quiz_grades.quiz in (15,16,17)
GROUP BY username
HAVING COUNT(*) = 3如果相同的用户If可能多次使用相同的测验,则需要应用DISTINCT:
HAVING COUNT(DISTINCT quiz) = 3https://stackoverflow.com/questions/30344706
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