考虑这个非常简单的程序:
#include <boost/type_erasure/is_placeholder.hpp>
#include <boost/iterator/iterator_adaptor.hpp>
int main()
{
return 0;
}这无法通过以下命令进行编译:
include/boost/type_erasure/is_placeholder.hpp:31:33: error: reference to 'use_default' is ambiguous
struct is_placeholder< ::boost::use_default> : ::boost::mpl::false_ {};
^
include/boost/iterator/iterator_adaptor.hpp:44:18: note: candidate found by name lookup is 'boost::use_default'
using iterators::use_default;
^
include/boost/type_erasure/is_placeholder.hpp:21:8: note: candidate found by name lookup is 'boost::use_default'
struct use_default;
^
1 error generated.我不想去更改那些头文件。我如何解决这个问题?
发布于 2015-09-01 09:50:19
临时解决方案将被替换
struct use_default;在` `boost/type_erasure/is_placeholder.hpp‘中
namespace iterators {
struct use_default;
}
using iterators::use_default;它可以在` `boost/iterator/iterator_adaptor.hpp‘中找到。
https://stackoverflow.com/questions/30247935
复制相似问题