将QScopedPointer传递给函数

Question

如何将QScopedPointer对象传递给另一个类似的函数：

bool addChild(QScopedPointer<TreeNodeInterface> content){
   TreeNode* node = new TreeNode(content);
}

TreeNode：

TreeNode::TreeNode(QScopedPointer<TreeNodeInterface> content)
{
    mContent.reset(content.take());
}

I get: error：'QScopedPointer::QScopedPointer(const QScopedPointer&) with T= TreeNodeInterface；Cleanup = QScopedPointerDeleter‘是私有的

我该怎么解决它呢？谢谢!

Answer 1

您可以通过接受对指针的引用来完成此操作-这样您就可以将null本地指针与传递给您的指针交换：

#include <QScopedPointer>
#include <QDebug>

class T {
   Q_DISABLE_COPY(T)
public:
   T() { qDebug() << "Constructed" << this; }
   ~T() { qDebug() << "Destructed" << this; }
   void act() { qDebug() << "Acting on" << this; }
};

void foo(QScopedPointer<T> & p)
{
   using std::swap;
   QScopedPointer<T> local;
   swap(local, p);
   local->act();
}

int main()
{
   QScopedPointer<T> p(new T);
   foo(p);
   qDebug() << "foo has returned";
   return 0;
}

输出：

Constructed 0x7ff5e9c00220 
Acting on 0x7ff5e9c00220 
Destructed 0x7ff5e9c00220 
foo has returned