如何获取图像文件并在屏幕上打开它？

Question

我试图从本地目录打开一个jpg图像文件，并简单地将其绘制到屏幕上。

这是代码，但是图像位置并没有引用并得到所有类型的错误！

错误是：“找不到符号变量g”，它指的是我试图绘制图像的位置(见代码底部附近)

我是一个学习者--很抱歉这是显而易见的！感谢您的帮助:-)

import comp102.*;
import java.util.Scanner;
import java.awt.*;


/** A program that plays Rock-Paper-Scissors with the user.
*/
public class RPS{

    String paper = "paper";
    String rock = "rock";
    String scissors = "scissors";    

        /** Play one round of RPS and print out the choices and the result */
    public void playRound(){

        String paper = "paper";
        String rock = "rock";
        String scissors = "scissors";    

        System.out.print ('\f'); // clears screen
        Scanner currentUserSelection = new Scanner(System.in);

        UI.initialise();
        String enterText = null;
        System.out.println("Make your Selection; Paper, Rock or Scissors: ");
        enterText = currentUserSelection.next();

        if(enterText == paper){
        drawImage("paper-left.jpg", 100, 100, null);
        }

    }

}

Answer 1

使用Graphics设置变量

public void paint(Graphics g){
//image code
}