如果最后一个字符是逗号，则删除新行

Question

您好，我正在尝试操作使用nsradmin (networker)生成的报告，顺便说一句，这是一个简单的输出(大约有5000行)

                   name: SERVER1;
                   group: FIRST;
                save set: "C:\\", "VSS SYSTEM FILESET:\\", "VSS OTHER:\\",
                          "VSS USER DATA:\\", "VSS SYSTEM SERVICES:\\",
                          "VSS SYSTEM BOOT:\\";
          client OS type: Windows NT Server on Intel;
       NetWorker version: 7.4.4.Build.634;


                    name: SERVER2;
                   group: NGDC_SO_5;
                group: NGDC_SO_5;
                          "VSS OTHER:\\", "VSS USER DATA:\\",
                          "VSS SYSTEM SERVICES:\\", "VSS SYSTEM BOOT:\\",
                          "C:\\";
                           client OS type: Windows NT Server on Intel;
                         NetWorker version: 7.4.4.Build.634;

我想要一份这种格式的报告

name: SERVER1;group: NGDC_SO_5;VSS OTHER:\\", "VSS USER DATA:\\"client OS type: Windows NT Server on Intel;

name: SERVER2;group: NGDC_SO_5;VSS OTHER:\\", "VSS USER DATA:\\"client OS type: Windows NT Server on Intel;

第一行总是以NAME开头，最后一行是“一个空行。不幸的是，我尝试了，但没有成功

Answer 1

使用awk在name之间合并行

awk '/name/{if (x)print x;x="";}{x=(!x)?$0:x","$0;}END{print x;}' inputfile

Answer 2

这里是一个非常快速和肮脏的刺刀，看看它是否接近你正在寻找的东西

awk '
""    {print saved; saved=""; next}
      {saved = saved " " $0}
END   {print saved}
' filename

你可以用无数种方法来提炼它