在atmega32中通过串行外围接口将数据分量从实时输入数据中分离出来

Question

我让三个atmega32通过SPI协议向蓝牙模块发送三组感应值(加速计、陀螺仪、磁力计)。我收到了蓝牙数据，但它是这样传过来的，

0.00,0.00,0.00,0.00,0.00,0.00,0.00,0.00,0.00,54.00

0.00,0.00,0.00,0.00,0.00,0.00,0.00,0.00,0.00,51.00

0.00,0.00,0.00,0.00,0.00,0.00,0.00,0.00,0.00,53.00

它是作为csv数据接收的，我无法分离单独的组件。我希望将它们存储在单独的变量中(如x1、y1、z1等)。

下面是我的代码：

# Author: P. Vinod Ranganath
# Description: Receiving data from ATmega32 via bluetooth
# Date: 27/04/2015


import bluetooth
import sys

#address of the bluetooth device
addr = "00:06:66:61:1E:76"
#port number
port = 1

#create socket and connect to it
socket = bluetooth.BluetoothSocket(bluetooth.RFCOMM)
socket.connect((addr, port))




#if there is an incoming transmission, enter loop
while True:
    #receive transmitted data
    data = socket.recv(1024) 

    #print data
    sys.stdout.write(data)  

Answer 1

Python有一个csv模块，它可以完成你通常想要的所有CSV解析。

在您的示例中，它甚至更简单: python中的字符串具有split(char)方法，因此

data.split(",") 

应该会给你一个子字符串的数组：

["0.0", "0.0", ....

现在，你想要浮点数，对吧？

坚持你最喜欢的Python教程(真的，读一读吧！)并这样做

values = [float(substring) for substring in data.split(",")]

因此，values是一个浮点数数组。

然后，您可以执行以下操作

x1 = values[10]

但您通常不希望这样做-将这种类型的数据作为数组通常更有用。

Answer 2

def get_words(data):
      l = []
      w = ''
     for c in data.lower():
          if c in '\r \n ,':
              if w != '': 
                 l.append(w)
                 w = ''
              else:
                 w = w + c
          if w != '': 
              l.append(w)
return l

在堆栈溢出时发现了这个。

它分离不同的元素并在没有errors.But的情况下进行浮点转换，列表不会按顺序填充(随机地从最后一项到第二位，依此类推)