使用不同的参数同时运行相同的函数

Question

我一直在尝试做一个小的python程序来监控和返回来自不同服务器的ping结果。我已经到了point序列中的每个设备都变得低效和缺乏性能的地步。我想在我的python上同时连续ping我的每个目标。

对此最好的方法是什么？耽误您时间，实在对不起

def get_latency(ip_address, port):
    from tcp_latency import measure_latency
    from datetime import datetime
    now = datetime.now()
    current_time = now.strftime("%Y-%m-%d %H:%M:%S")
    latency = str(measure_latency(host=ip_address, port=port, runs=1, timeout=1))[1:-1]
    #add to table and upload to database function()

ip_address_list = [('google.com', '80'), ('bing.com', '80')]


#Problem
#run function simultaneously but with different arguments
get_latency(ip_address_list[0][0], ip_address_list[0][1])
get_latency(ip_address_list[1][0], ip_address_list[1][1])

Answer 1

For循环不能同时运行。

您可以使用线程来同时运行。

请看以下内容：

import threading

def get_latency(ip_address, port):
    from tcp_latency import measure_latency
    from datetime import datetime
    now = datetime.now()
    current_time = now.strftime("%Y-%m-%d %H:%M:%S")
    latency = str(measure_latency(host=ip_address, port=port, runs=1, timeout=1))[1:-1]
    #add to table and upload to database function()

ip_address_list = [('google.com', '80'), ('bing.com', '80')]

#adding to thread

t1 = threading.Thread(target=get_latency, args=(ip_address_list[0][0], ip_address_list[0][1])) 

t2 = threading.Thread(target=get_latency, args=(ip_address_list[1][0], ip_address_list[1][1])) 

# starting thread 
t1.start() 
t2.start() 

# wait until thread 1 is completely executed 
t1.join() 
# wait until thread 2 is completely executed 
t2.join() 

# both threads completely executed 
print("Done!") 

Answer 2

您可以使用for循环来实现此目的。如下所示：

for i in range(len(ip_address_list)):
    print(get_latency(ip_address_list[i][0], ip_address_list[i][1]))

此外，还应在编写函数之前定义模块并返回结果

from tcp_latency import measure_latency
from datetime import datetime

def get_latency(ip_address, port):
    .
    .
    .
    return results