如何改进当前代码以获得正确的结果

Question

我有一些活动。根据插入day.like，每周在应用程序中显示事件

event one > Friday
event two > sat
event three > sun

因此，每周五凌晨2点到2点在应用程序中显示事件1

我搞不懂如何管理凌晨2点到凌晨2点我已经创建了一个逻辑，但它无法给我正确的计算

    $input = time();
                $day = date('D', $input );

                switch ($day) {
                    case 'Sun':
                        $finalday='0';
                        break;
                    case 'Mon':
                        $finalday='1';
                        break;
                    case 'Tue':
                        $finalday='2';
                        break;
                    case 'Wed':
                        $finalday='3';
                        break;
                    case 'Thu':
                        $finalday='4';
                        break;
                    case 'Fri':
                        $finalday='5';
                        break;
                    case 'Sat':
                        $finalday='6';
                        break;
                }




                $now = time();
                $event_time = strtotime("02:00 am");

                if( ($now - $event_time) < 0) // 5 minutes * 60 seconds, replace with 300 if you'd like
                {
                    //before day
                    if($finalday=='0')
                    {

                        $query_day='6';
                    }
                    else
                    {
                        $query_day=$finalday-1;
                    }


                }
                else
                {
//current day
                    $query_day=$finalday;
                }

如何根据插入日期显示每个事件在凌晨2点到2点之间的准确时间

假设现在是中午12点，所以今天是星期五，但事件一将从凌晨2点播放到下一个1.59AM，然后事件2将从凌晨2点播放到下午1.59AM(星期六)。

通过这种方式，将显示下一个弱自动事件

Answer 1

试着这样做，让您的代码看起来更优雅一点，而不是那么笨拙

$dayOfWeek = date('w'); //0 for Sunday through 6 for Saturday
$hourOfDay = date('H'); //0-23
$eventOne = null;
$eventTwo = null;
$eventThree = null;

//logic structure to set events
if($hourOfDay >= 0 && $hourOfDay < 2){
    $dayOfWeek -= 1; //set to previous day if earlier than 2AM
    $dayOfWeek = $dayOfWeek == 0 ? 6 : $dayOfWeek; //quick check to set to Sunday if day was on Monday
    $eventOne = $dayOfWeek;
    $eventTwo = $dayOfWeek+1;
    $eventThree = $dayOfWeek+2;

    //single line if statements to correct weekly overflow
    if($eventTwo == 7) $eventTwo = 0;
    if($eventThree == 7) $eventThree = 0;
    if($eventThree == 8) $eventThree = 1;
}else{

    $eventOne = $dayOfWeek;
    $eventTwo = $dayOfWeek+1;
    $eventThree = $dayOfWeek+2;

    //single line if statements to correct weekly overflow
    if($eventTwo == 7) $eventTwo = 0;
    if($eventThree == 7) $eventThree = 0;
    if($eventThree == 8) $eventThree = 1;
}



function getDayOfEvent($event){
    switch($event){
        case 0: return "Sunday"; break;
        case 1: return "Monday"; break;
        case 2: return "Tuesday"; break;
        case 3: return "Wednesay"; break;
        case 4: return "Thursday"; break;
        case 5: return "Friday"; break;
        case 6: return "Saturday"; break;
    }   
}

print "Event One: ". getDayOfEvent($eventOne)."\nEvent Two: ".getDayOfEvent($eventTwo)."\nEvent Three: ".getDayOfEvent($eventThree);

如果这样的东西对你有效，请让我知道。

这是一个粘贴在CodePad上的文件，如果你想使用http://codepad.org/SLcTeGEt，你可以稍微修改一下代码

Answer 2

试试这个程序..。也许就是你想要的。(你的问题非常令人困惑。)

/* Day Of Week 0 = Sun ... 6 = Sat
 * ---------------------------------
 * Day      Hour     Result    Case
 * ---------------------------------
 *  5     00 - 02   No event    C
 *  5     02 - 24   Event 1     B
 *  6     00 - 02   Event 1     A
 *  6     02 - 24   Event 2     B
 *  0     00 - 02   Event 2     A
 *  0     02 - 24   Event 3     B
 *  1     00 - 02   Event 3     A
 *  1     02 - 24   No Event    C
 * Other  Other     No Event    C
 * ---------------------------------
 */

function getEvent( $timestamp, $eventTime ) {
    $d = (int) date( 'w', $timestamp ); // Day
    $h = (int) date( 'G', $timestamp ); // Hour
    $event = $h < $eventTime && ( $d > 5 || $d < 2 )  // Case A
        ? ( $d + 2 ) % 7                              // Case A Result
        : ( $h >= $eventTime && ( $d > 4 || $d == 0 ) // Case B
            ? ( $d + 3 ) % 7                          // Case B Result
            : null );                                 // Case C Result
    printf ( "\n%s %02d:00 :: %s",                    // ... and show
             date( 'D', strtotime( "Sunday +{$d} days" ) ),
             $h, $event ? "Event $event" : 'No event' );
}

$eventTime = 2;
echo '<pre>';
/* Testing the getEvent function */
for ( $timestamp = mktime( 23, 0, 0, 4, 30, 2015 ); // Thu at 23:00
      $timestamp <= mktime( 22, 0, 0, 5, 7, 2015 ); // Thu at 22:00
      $timestamp += 3600 * 2 ) {                    // Each 2 hours
    getEvent( $timestamp, $eventTime );
}

?>