XmlSerializer WebResponse

Question

我有一个包含许多名称的XML，就像一个列表：

<apelidos>
    <apelido>Casmilo</apelido>
    <apelido>Castro</apelido>
</apelidos>

我的模型是这样的：

namespace IdCel.Model
{
   [XmlTypeAttribute(AnonymousType = true)]
   public class apelidos
   {
       [XmlArray("apelidos")]
       [XmlArrayItem("apelidos")]
       public List<apelido> apelidosNomes { get; set; }

       public apelidos()
       {
           apelidosNomes = new List<apelido>();
       }
   }

   public class apelido
   {
       [XmlElement(ElementName = "apelido")]
       public string apelidoNome { get; set; }
   }
}

还有我的XmlSerializer

HttpWebRequest request = WebRequest.Create(uri) as HttpWebRequest;
XmlSerializer ser = new XmlSerializer(objetoLista.GetType());

WebResponse response = request.GetResponse();
var result = ser.Deserialize(response.GetResponseStream());

return result;

但是它不起作用，我用没有列表的XML做同样的代码，它工作得很好

Answer 1

如果您只需要读取apelido标记的内容，那么使用Linq To XML会快得多。例如：

var xml = @"<apelidos>
                <apelido>Casmilo</apelido>
                <apelido>Castro</apelido>
            </apelidos>";

var doc = XDocument.Parse(xml);
var apelidos = from apelido in doc.Descendants("apelido")
               select apelido.Value;

这将为您提供一个包含所有名称的IEnumerable<string>作为结果。

编辑:要从web加载XML，您可以执行以下操作：

HttpWebRequest request = WebRequest.Create(uri) as HttpWebRequest;

WebResponse response = request.GetResponse();
var doc = XDocument.Load(response.GetResponseStream());

Answer 2

现在它起作用了！我这样做了：

[Serializable()]
public class apelidos
{
    [System.Xml.Serialization.XmlElement("apelido")]
    public List<string> apelido { get; set; }
}

还有这个：

HttpWebRequest request = WebRequest.Create(uri)
           as HttpWebRequest;

        XmlSerializer ser = new XmlSerializer(objetoLista.GetType());

        WebResponse response = request.GetResponse();
        var result = ser.Deserialize(response.GetResponseStream());

        return result;