如何访问这个javascript对象？

Question

{"profit_center" : 

{"branches":

[

{"branch":      {"work_order":"1","cutover":"1","site_survey":"1","branch_number":"3310","quote":"1","configuration":"1","purchase_order":"1","hardware_swap":"1"}},

{"branch":{"work_order":"1","cutover":"1","site_survey":"1","branch_number":"3311","quote":"1","configuration":"1","purchase_order":"1","hardware_swap":"1"}},

{"branch":{"work_order":"1","cutover":"0","site_survey":"1","branch_number":"3312","quote":"1","configuration":"1","purchase_order":"1","hardware_swap":"1"}},

{"branch":{"work_order":"1","cutover":"1","site_survey":"1","branch_number":"3313","quote":"1","configuration":"1","purchase_order":"1","hardware_swap":"1"}},

{"branch":{"work_order":"1","cutover":"0","site_survey":"1","branch_number":"3314","quote":"1","configuration":"1","purchase_order":"1","hardware_swap":"1"}},

{"branch":{"work_order":"1","cutover":"1","site_survey":"1","branch_number":"3315","quote":"1","configuration":"1","purchase_order":"1","hardware_swap":"1"}}

],


"profit_center_name":"Alabama"}}

我试着通过这个在ajax中访问它，

data.profit_center //data here is the ajax variable e.g. function(data)

或通过此data["profit_center"]

但没那么走运

如何正确访问这个javascript对象。？

顺便说一句，上面的代码来自console.log(data)

编辑：

来自console.log(data.profit_center)和console.log(data["profit_center"])的结果未定义

Answer 1

首先解析您的数据，如果您还没有这样做的话。

例如，您可以像这样访问每个branch_number：

var branches = data.profit_center.branches;

for (var i = 0, l = branches.length; i < l; i++) {
  console.log(branches[i].branch.branch_number);
}

总之，profit_center是一个对象，而branches是一个对象数组。数组中的每个元素都包含一个包含多个键的分支对象。循环遍历branches数组，对于每个元素，使用键名称访问内部的分支对象以获取值。

利润中心名称可以通过访问profit_center对象上的profit_center_name键找到：

console.log(data.profit_center.profit_center_name); // Alabama

您甚至可以使用新的函数数组方法来查询数据，并只提取需要的分支。在这里，我使用filter拉取那些purchase_order等于2的对象。请注意，JSON中的数值是字符串，而不是整数。

var purchaseOrder2 = branches.filter(function (el) {
  return el.branch.purchase_order === '2';
});

Answer 2

您可以将data放在一个变量中，如下所示

var json = data

你可以像这样访问profit_center

alert(json.profit_center);

alert(json.profit_center.profit_center_name); //Alabama

for(var i =0 ;i<json.profit_center.branches.length;i++){ alert(json.profit_center.branches[i]); }

Answer 3

好了，我已经找到了为什么它是未定义的，它是一个json对象，所以我需要先解析它，然后才能像javascript对象一样访问它。

var json = JSON.parse(data);

那就是这样了。