反转ids

Question

我正在使用下面的代码获取更改in，然后进行循环...我需要在文件change_ids.txt..I中反转in需要一些最佳方法的想法?请提供您的想法。

with open(timedir + "/change_ids.txt", "wb") as f:
    check_call("ssh -p 29418 company.com "
        "gerrit query --commit-message --files --current-patch-set "
        "status:open project:platform/vendor/com-proprietary/code branch:master |"
        "grep refs |"
        "cut -f4 -d'/'",
            shell=True,   # need shell due to the pipes
            stdout=file)  # redirect to a file
 for line in open(timedir + "/change_ids.txt"):
#code

change_ids.txt包含

210717
210716
210715
210714
210713

Answer 1

这将从下到上处理这些行：

for line in reversed(list(open(timedir + "/gerrit_ids.txt"))):
    ...