日期存储在int(11)中,作为fuelphp的默认值。现在我想提取每个月和一年的数据,以便存档。使用mysql查询,条件为月(日期)=‘2月’和年(日期)= '2014‘。我尝试使用以下mysql查询,但无济于事。
SELECT
contents.*,
menus.menu_parent,
categories.category_alias
FROM
contents
LEFT JOIN
menus ON menus.link = contents.id
JOIN
categories ON categories.id = contents.category_id
WHERE
contents.status = '1' AND
DATE_FORMAT(FROM_UNIXTIME(contents.`published_date`), '%Y %M') = '2014 January' AND
contents.category_id = 3数据库中的日期值如下所示:2014.8.17- 1408212900 2015.3.27- 1427393700
存储到数据库期间:strtotime(日期)
我该如何解决这个问题呢?欢迎任何帮助/建议。提前谢谢。
发布于 2015-04-09 20:29:00
也许像这样的东西会对你有所帮助:
SELECT contents.*, menus.menu_parent, categories.category_alias
FROM contents
LEFT JOIN menus ON menus.link = contents.id
JOIN categories ON categories.id = contents.category_id
WHERE contents.status = '1'
AND MONTHNAME(FROM_UNIXTIME(last_activity)) = 'January'
AND YEAR(FROM_UNIXTIME(last_activity)) = 2014
AND contents.category_id = 3;您可以使用以下命令首先转换要与实际日期进行比较的字段
FROM_UNIXTIME有关MySQL中日期时间函数的更多信息,请访问:https://dev.mysql.com/doc/refman/5.5/en/date-and-time-functions.html
编辑:为了提高查询性能,您可以将这两种方法结合使用:
SELECT contents.*, menus.menu_parent, categories.category_alias
FROM contents
LEFT JOIN menus ON menus.link = contents.id
JOIN categories ON categories.id = contents.category_id
WHERE contents.status = '1'
AND DATE_FORMAT((FROM_UNIXTIME(last_activity)),'%M-%Y') = 'January-2014'
AND contents.category_id = 3;https://stackoverflow.com/questions/29538318
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