不带中断或继续的Python Make函数

Question

我有这个功能

def getInput(rows, cols, myList):
    myList = [[0]*(cols-2) for i in range(rows-2)] #creates the board
    for i in myList: # adds -1 to beginning and end of each list to make border
        i.append(-1)
        i.insert(0,-1)
    myList.insert(0,[-1]*(cols)) #adds top border
    myList.append([-1]*(cols)) #adds bottom border

    while True:
        rows = input("Please enter the row of a cell to turn on or 'q' to exit: ")
        if rows == 'q': # if q then end while loop
            break
        cols = input("Please enter the column of a cell to turn on: ")
        print()
        myList[int(rows)][int(cols)] = 1 # changes chosen cells from 0(dead) to 1(alive)
    return myList

我需要知道一种方法，让这个函数在不中断或继续的情况下。

Answer 1

我认为这应该可以做到：

...
rows = ""
while rows != 'q':
    rows = input("Please enter the row of a cell to turn on or 'q' to exit: ")
    if rows != 'q': # if q then end while loop
        cols = input("Please enter the column of a cell to turn on: ")
        print()
        myList[int(rows)][int(cols)] = 1 # changes chosen cells from 0(dead) to 1(alive)
return myList

只有当rows不是True时才进入if块，如果在任何运行中，rows初始化为"q"，那么while循环将在下一次运行时自动终止。

Answer 2

您可以拥有一个保存布尔值True的变量，并且可以在所需的基本条件if rows == 'q':中转换为False。

status = True
while status:
    rows = input("Please enter the row of a cell to turn on or 'q' to exit: ")
    if rows == 'q':
        status = False
        continue
    cols = input("Please enter the column of a cell to turn on: ")
    print()
    myList[int(rows)][int(cols)] = 1
return myList

如果您不想同时使用break和continue语句。然后，您应该返回myList，因为它将从终止while循环的函数中退出。

if rows == 'q':
    return myList

Answer 3

如何使用else来避免需要continue。

def getInput(rows, cols, myList):
    myList = [[0]*(cols-2) for i in range(rows-2)] #creates the board
    for i in myList: # adds -1 to beginning and end of each list to make border
        i.append(-1)
        i.insert(0,-1)
    myList.insert(0,[-1]*(cols)) #adds top border
    myList.append([-1]*(cols)) #adds bottom border
    run = True

    while run:
        rows = input("Please enter the row of a cell to turn on or 'q' to exit: ")
        if rows == 'q': # if q then end while loop
            run = False
        else:
            cols = input("Please enter the column of a cell to turn on: ")
            print()
            myList[int(rows)][int(cols)] = 1 # changes chosen cells from 0(dead) to 1(alive)
    return myList