用PIR激活继电器模块上的电磁铁

Question

所以我在arduino的3.3v引脚上运行PIR，arduino的gnd引脚，然后进入input 9。我调整了我的代码到网站，但它仍然不能工作。我希望继电器在PIR较低时打开，然后在PIR较高时关闭。我还需要PIR在注册另一个输入之前等待至少5秒。

​

#define RELAY_ON 1
#define RELAY_OFF 0

#define Relay_1  2  // Arduino Digital I/O pin number
#define Relay_2  3
#define Relay_3  4
#define Relay_4  5
#define Relay_5  6  
#define Relay_6  7


/*-----( Declare Variables )-----*/
int waittime; // Delay between changes

int state = LOW;             // by default, no motion detected
int val = 0;                 // variable to store the sensor status (value)
int pirPin = 9;    //the digital pin connected to the PIR sensor's output



void setup()   /****** SETUP: RUNS ONCE ******/
{
  waittime = 1000;
  pinMode(pirPin, INPUT);     // initialize sensor as an input
  Serial.begin(9600);        // initialize serial
    
//-------( Initialize Pins so relays are active at reset)----
  digitalWrite(Relay_1, RELAY_ON);
  digitalWrite(Relay_2, RELAY_ON);
  digitalWrite(Relay_3, RELAY_ON);
  digitalWrite(Relay_4, RELAY_ON);  
  digitalWrite(Relay_5, RELAY_ON);
  digitalWrite(Relay_6, RELAY_ON);
//---( THEN set pins as outputs )----  

  digitalWrite(pirPin, LOW);  
  pinMode(Relay_1, OUTPUT);   
  pinMode(Relay_2, OUTPUT);  
  pinMode(Relay_3, OUTPUT);  
  pinMode(Relay_4, OUTPUT);    
  pinMode(Relay_5, OUTPUT);   
  pinMode(Relay_6, OUTPUT);  
  delay(4000); //Check that all relays are active at Reset
  
}//--(end setup )---


void loop()   /****** LOOP: RUNS CONSTANTLY ******/
{

val = digitalRead(pirPin);   // read sensor value
if (val == HIGH) {           // check if the sensor is HIGH   
//---( Turn all 8 relays ON in pairs)---  

  digitalWrite(Relay_1, RELAY_OFF);// set the Relay OFF
  digitalWrite(Relay_2, RELAY_OFF);// set the Relay OFF
  delay(waittime);              // wait for a second  
  
  digitalWrite(Relay_3, RELAY_OFF);// set the Relay OFF 
  digitalWrite(Relay_4, RELAY_OFF);// set the Relay OFF
  delay(waittime);
  
  digitalWrite(Relay_5, RELAY_OFF);// set the Relay OFF
  digitalWrite(Relay_6, RELAY_OFF);// set the Relay OFF
  delay(5000);              // wait see all relays ON  
  
  if (state == LOW) {
      Serial.println("Motion detected!"); 
      state = HIGH;       // update variable state to HIGH
    }
  } 

  else {
    
//---( Turn all 8 relays OFF in pairs)---

  digitalWrite(Relay_1, RELAY_ON);// set the Relay ON
  digitalWrite(Relay_2, RELAY_ON);// set the Relay ON
  delay(waittime);   
  
  digitalWrite(Relay_3, RELAY_ON);// set the Relay ON
  digitalWrite(Relay_4, RELAY_ON);// set the Relay ON
  delay(waittime);
  
  digitalWrite(Relay_5, RELAY_ON);// set the Relay ON
  digitalWrite(Relay_6, RELAY_ON);// set the Relay ON
  delay(10000);              // wait see all relays OFF
  
    
       
       
 if (state == HIGH){
        Serial.println("Motion stopped!");
        state = LOW;       // update variable state to LOW
       }
     }
  }

​

Answer 1

当事情不像我期望的那样工作时，我总是先看一下线路。编写一些简单的测试代码，除了打印PIR的信号引脚的状态之外，什么也不做。它会在你期望的时候涨得很高吗？它会在你预期的时候走低吗？如果不是这样，那么您就有了连接问题。在考虑其他编程之前，先弄清楚这一点。

至于wiring...you，在你的描述中没有提到上拉电阻-大多数PIR模块(至少是我工作过的那些模块)在其信号引脚上需要一个上拉电阻，以便在没有信号时将输出拉高。也许你有一个，只是没有提到它，但如果没有，那么这可能是你的问题-没有上拉电阻，你的输出是浮动的，你的设备将不会像你期望的那样工作。也就是说，大多数Arduino板(你没有说你使用的是哪一个)在数字引脚上有内部上拉，但你必须通过执行以下操作来启用它们：

pinMode(pin, INPUT);      
digitalWrite(pin, HIGH); 

您在setup()例程中将信号引脚设置为低电平，这会关闭内部上拉电阻。将其更改为高以打开它，这样就可以避免添加外部电阻。

另外，你确定你的PIR模块运行在3.3V电压下吗？有些需要5V。请查看它的数据表以确定。