Pyomo输出错误

Question

我正在使用pyomo包实现一个优化问题。我正在尝试pyomo在线文档中提供的一个示例问题。但是，当我试图解决它的时候，我得到了错误。

使用的python代码：

from __future__ import division
from pyomo.environ import *

model = AbstractModel()

model.Nodes = Set()
model.Arcs = Set(dimen=2)

model.Flow = Var(model.Arcs, domain=NonNegativeReals)
model.FlowCost = Param(model.Arcs)
model.Demand = Param(model.Nodes)
model.Supply = Param(model.Nodes)

def Obj_rule(model):
    return summation(model.FlowCost, model.Flow)

model.Obj = Objective(rule=Obj_rule, sense=minimize)


def FlowBalance_rule(model, node):
    return model.Supply[node] \
        + sum(model.Flow[i, node] for i in model.Nodes if (i,node) in model.Arcs) \
        - model.Demand[node] \
        - sum(model.Flow[node, j] for j in model.Nodes if (j,node) in model.Arcs) \
        == 0

model.FlowBalance = Constraint(model.Nodes, rule=FlowBalance_rule)

并且，数据文件是：

set Nodes := CityA CityB CityC ;
set Arcs :=
CityA CityB
CityA CityC
CityC CityB
;
param : FlowCost :=
CityA CityB 1.4
CityA CityC 2.7
CityC CityB 1.6
;
param Demand :=
CityA 0
CityB 1
CityC 1
;
param Supply :=
CityA 2
CityB 0
CityC 0
;

当我试图解决这个问题时，我得到了以下错误。

[    0.00] Setting up Pyomo environment
[    0.00] Applying Pyomo preprocessing actions
[    0.01] Creating model
ERROR: Rule failed when generating expression for constraint FlowBalance with index CityB:
        KeyError: "Error accessing indexed component: Index '('CityB', 'CityC')' is not valid for array component 'Flow'"
ERROR: Constructing component 'FlowBalance' from data=None failed:
        KeyError: "Error accessing indexed component: Index '('CityB', 'CityC')' is not valid for array component 'Flow'"
ERROR: Unexpected exception while running model test.py:
        Error accessing indexed component: Index '('CityB', 'CityC')' is not valid for array component 'Flow'

Answer 1

您在FlowBalance_rule中有以下拼写错误

sum(model.Flow[node, j] for j in model.Nodes if (j,node) in model.Arcs)

其中索引model.Flow[node,j]和条件if (j,node) in model.Arcs导致错误。

我假设您想要颠倒条件元组的顺序，如下所示

def FlowBalance_rule(model, node):
    return model.Supply[node] \
        + sum(model.Flow[i, node] for i in model.Nodes if (i,node) in model.Arcs) \
        - model.Demand[node] \
        - sum(model.Flow[node, j] for j in model.Nodes if (node,j) in model.Arcs) \
        == 0