scala xml EntityResolver等价物

Question

我一直在尝试让scala的xml解析来允许我设置EntityResolver。

我做错了什么，但是我找不到实质性的文档。将scala的解析器指向dtd文件的正确位置的正确方法是什么？

object MyXML {
  def loadFile(file: File): Node = {

    println("loadFile called")

    val parser: SAXParser = scala.xml.XML.parser
    parser.getParser.setEntityResolver(new MyXMLEntityResolver)
    // Also tried: parser.getXMLReader.setEntityResolver...    

    val inputSource = new InputSource(file.getAbsolutePath)

    val loader = scala.xml.XML.withSAXParser(parser)


    loader.loadFile(file)

    //scala.xml.XML.loadXML(inputSource, parser)
  }

  class MyXMLEntityResolver extends EntityResolver {
    override def resolveEntity(publicId: String, systemId: String): InputSource = {

      println("Resolve called!")

      new InputSource(systemId)

    }
  }
}

// prints only "loadFile called"

Answer 1

答案是，要覆盖的重要内容是XMLLoader[T]中的adapter方法，它具有执行正确解析的适配器，而不是设置parser方法的EntityResolver (即使覆盖它也不起作用！)

所以，我有一个这样的类，它似乎可以解决这个问题

class MyXMLParser extends XMLLoader[Elem] {
 override def adapter = {
   new MyXMLAdapter
  }
}

class PhysicsXMLAdapter extends NoBindingFactoryAdapter {
  val myEntityResolver = new MyEntityResolver
  override def resolveEntity(publicId: String, systemId: String): InputSource = {
     myEntityResolver.resolveEntity(publicId, systemId)
  }
}