我无法让Java接受键盘输入字符串

Question

我想知道如何让我的java程序中的键盘响应正常工作，并照常继续游戏。

我知道代码有点凌乱，数组可能更适合，但在这个例子中，我只想要关于键盘输入的答案。

在到达if和if else语句之前，游戏运行得足够好。那我就真的不知道该怎么修了。

import java.util.Random;
import java.util.Scanner;

class blackjack {
    public static void main(String[] args) {
        Random r = new Random();

        Scanner keyboard = new Scanner(System.in);
        String money;
        String name;
        String hiscore;
        String h;
        String s;

        int card1 = 1 + r.nextInt(11);
        int card2 = 1 + r.nextInt(11);
        int card3 = 1 + r.nextInt(11);
        int card4 = 1 + r.nextInt(11);
        int card5 = 1 + r.nextInt(11);
        int card6 = 1 + r.nextInt(11);
        int card7 = 1 + r.nextInt(11);
        int card8 = 1 + r.nextInt(11);
        int card9 = 1 + r.nextInt(11);
        int card10 = 1 + r.nextInt(11);
        int card11 = 1 + r.nextInt(11);
        int card12 = 1 + r.nextInt(11);
        int card13 = 1 + r.nextInt(11);

        int total1 = card2 + card3;
        int total2 = total1 + card4;

        System.out.println("Welcome to Blackjack ! ");
        System.out.println("Score as close to 21 without going over to win ");
        System.out.println("What is your name?");
        name = keyboard.nextLine();
        System.out.println("Hello " + name);
        System.out.println("Let's play some BlackJack!");

        System.out.println("The dealer shows: \n\t\t" + card1);
        System.out.println("Your first card is: \n\t\t " + card2);
        System.out.println("Your second card is: \n\t\t" + card3);
        System.out.println("giving you a total of " + total1);
        System.out.println("Would you like to (H)it or (S)tick?");
        if h = keyboard.nextLine();
        System.out.println("Your next card is " + card4);
        System.out.println("Giving you a new total of: " + total2);
        if else s = keyboard.nextLine();
        System.out.println("your final score is: "total1);
    }
}

Answer 1

该if (和if-else)语句是已损坏的。它不是有效语法。正确的语法应该是：

if(h = keyboard.nextLine());

请注意，我说过这是正确的语法，但这肯定不会做您想要它做的事情。看起来你想要做的是对照预定的字符串"h“和"s”进行检查。

将变量存储在某个地方，然后进行比较。请记住，要比较Java语言中的字符串，需要使用.equals()。

String response = keyboard.nextLine();
if("h".equals(response)) {
    // perform operations here
} else if("s".equals(response)) {
    // perform operations here
}