我写了一个小函数,将一个数字拆分成逗号,但我必须对这个数字运行太多次。你能给我推荐一种更好的方法吗?
public static function getCommaString(value:Number):String {
var stringValue:String = value.toString();
if (stringValue.length <= 3) {
return stringValue;
}
var i:int = stringValue.length % 3;
if (i == 0) {
i = 3;
}
for (; i < stringValue.length; i += 4 ) {
var part1:String = stringValue.substr(0, i);
var part2:String = stringValue.substr(i, stringValue.length);
stringValue = part1.concat(",", part2);
}
return stringValue;
}发布于 2012-11-16 12:54:26
我整理了一个测试类,将您的解决方案与其他解决方案进行比较,包括来自此blog post的解决方案和来自此相关StackExchange question的解决方案,并以一致的方式对它们进行格式化以便于比较:
package
{
public class CommaNumberSolutions
{
public static function commaify( input:Number ):String
{
var split:Array = input.toString().split( '.' ),
front:String = split[0],
back:String = ( split.length > 1 ) ? "." + split[1] : null,
n:int = input < 0 ? 2 : 1,
commas:int = Math.floor( (front.length - n) / 3 ),
i:int = 1;
for ( ; i <= commas; i++ )
{
n = front.length - (3 * i + i - 1);
front = front.slice( 0, n ) + "," + front.slice( n );
}
if ( back )
return front + back;
else
return front;
}
public static function getCommaString( input:Number ):String
{
var s:String = input.toString();
if ( s.length <= 3 )
return s;
var i:int = s.length % 3;
if ( i == 0 )
i = 3;
for ( ; i < s.length; i += 4 )
{
var part1:String = s.substr(0, i);
var part2:String = s.substr(i, s.length);
s = part1.concat(",", part2);
}
return s;
}
public static function formatNumber( input:Number ):String
{
var s:String = input.toString()
var result:String = ''
while ( s.length > 3 )
{
var chunk:String = s.substr(-3)
s = s.substr(0, s.length - 3)
result = ',' + chunk + result
}
if ( s.length > 0 )
result = s + result
return result
}
public static function commaCoder( input:Number ):String
{
var s:String = "";
var len:Number = input.toString().length;
for ( var i:int = 0; i < len; i++ )
{
if ( (len-i) % 3 == 0 && i != 0)
s += ",";
s += input.toString().charAt(i);
}
return s;
}
public static function regex1( input:Number ):String
{
return input.toString().replace( /-{0,1}(\d)(?=(\d\d\d)+$)/g, "$1," );
}
public static function regex2( input:Number ):String
{
return input.toString().replace( /-{0,1}\d{1,3}(?=(\d{3})+(?!\d))/g , "$&,")
}
public static function addCommas( input:Number ):String
{
var negative:String = "";
if ( input < 0 )
{
negative = "-";
input = Math.abs(input);
}
var s:String = input.toString();
var results:Array = s.split(/\./);
s = results[0];
if ( s.length > 3 )
{
var mod:Number = s.length % 3;
var output:String = s.substr(0, mod);
for ( var i:Number = mod; i < s.length; i += 3 )
{
output += ((mod == 0 && i == 0) ? "" : ",") + s.substr(i, 3);
}
if ( results.length > 1 )
{
if ( results[1].length == 1 )
return negative + output + "." + results[1] + "0";
else
return negative + output + "." + results[1];
}
else
return negative + output;
}
if ( results.length > 1 )
{
if ( results[1].length == 1 )
return negative + s + "." + results[1] + "0";
else
return negative + s + "." + results[1];
}
else
return negative + s;
}
}
}你可以在my other answer上看到更详细的分析,但你可以比较每个解决方案的紧凑性,并将其与其准确性和性能进行权衡,但是为了简洁起见,这个解决方案是最准确和性能最好的(尽管不是最紧凑的):
public function commaify( input:Number ):String
{
var split:Array = input.toString().split( '.' ),
front:String = split[0],
back:String = ( split.length > 1 ) ? "." + split[1] : null,
n:int = input < 0 ? 2 : 1,
commas:int = Math.floor( (front.length - n) / 3 ),
i:int = 1;
for ( ; i <= commas; i++ )
{
n = front.length - (3 * i + i - 1);
front = front.slice( 0, n ) + "," + front.slice( n );
}
if ( back )
return front + back;
else
return front;
}https://stackoverflow.com/questions/11407392
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