我有一个.json文件,我正在将其序列化到Swift字典中。
typealias Dict = Dictionary<String,AnyObject>
func loadDictionaryFromJSON(filePath:String) -> Dict
{
var JSONData:NSData! = NSData.dataWithContentsOfMappedFile(filePath) as NSData
var JSONError:NSError?
let swiftObject:AnyObject = NSJSONSerialization.JSONObjectWithData(JSONData, options: NSJSONReadingOptions.AllowFragments, error: &JSONError)!
if let nsDictionaryObject = swiftObject as? NSDictionary
{
if let dictionaryObject = nsDictionaryObject as Dictionary?
{
return dictionaryObject as Dict
}else
{
println("Error could not make dictionary from NSDictionary in \(self)")
}
}else
{
"Error could not make NSDictionary in \(self)"
}
println("Empty dictionary passed, fix it!")
return Dict()
}然而,我现在在获取对象时遇到了问题。我的.json基本上是一个字典的字典(具有不同级别的嵌套)。因此,首先,我抓取顶层的每个对象(它们都是字典)。
for object in objects
{
var dict:Dictionary<String,AnyObject> = object
}但是,上面的代码行抛出了错误
(key: AnyObject, value: AnyObject)' is not convertible to 'Dictionary<String, AnyObject>如何正确地将字典中的每个对象转换为Dictionary <String,AnyObject>
发布于 2015-02-26 05:08:55
尖括号是古老的Swift AFAICT (协议除外?)为什么需要类型别名?如果你创建了它,为什么不在你的循环中使用它呢?
你能去掉别名和尖括号,在任何地方使用格式,看看会发生什么吗?
例如,下面的方法是否工作得更好?
for o in objects {
var dict = o as [String : AnyObject]
}如果对象已经被输入,你可以只调用它的字典并这样做:
for dict in dictionaries {
continue
}发布于 2015-02-26 05:15:38
for (key,value) in objects
{
var object:Dict = value as Dict
}结果是它给了我一个元组,我需要将这个值转换为一个字典。
有关详细信息,请参阅'(key: AnyObject, value: AnyObject)' does not have a member named 'subscript'。
https://stackoverflow.com/questions/28729528
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