引用类型数组？

Question

我尝试在两个不同的数组中存储相同的数据:一个是"spots“的二维数组，另一个是对象的数组，它也包含一个"spots”数组。

数组的索引是不同的，但我可以更改一个数组中的信息，它也会在另一个数组中更改。我的印象是数组包含引用类型，所以因为第二个数组(tileData)是由第一个数组(gameBoardData)组成的，所以当我更改tile中的数组时，为什么不更改gameBoardData中的数据？磁贴不是由对gameBoardData的引用构成的吗？如果不是，我该如何做我所描述的？

    public Spot[,] gameBoardData { get; private set; }
    public Tile[] tileData { get; private set; }

    private void initializeBoard()
    {
        this.gameBoardData = new Spot[4, 4];

        for (int row = 0; row < 4; row++)
        {
            for (int column = 0; column < 4; column++)
            {
                this.gameBoardData[row, column] = new Spot();
                this.gameBoardData[row, column].pieceState = 0;
            }
        }

        Tile tile1 = new Tile( new Spot[4] { gameBoardData[0, 0], gameBoardData[0, 1], gameBoardData[1, 1], gameBoardData[1, 0] });
        Tile tile2 = new Tile(new Spot[4] { gameBoardData[0, 2], gameBoardData[0, 3], gameBoardData[1, 3], gameBoardData[2, 2] });
        Tile tile3 = new Tile(new Spot[4] { gameBoardData[2, 0], gameBoardData[2, 1], gameBoardData[3, 1], gameBoardData[3, 0] });
        Tile tile4 = new Tile(new Spot[4] { gameBoardData[2, 2], gameBoardData[2, 3], gameBoardData[3, 3], gameBoardData[3, 2] });
        this.tileData = new Tile[4] { tile1, tile2, tile3, tile4 };

    }

Answer 1

我不确定为什么这些更改没有反映给您。下面是一个示例控制台应用程序，其中反映了这些更改。

using System;

namespace test
{
    class Program
    {
        static void Main(string[] args)
        {
            var board = new Board();
            board.InitializeBoard();
        }      
    }

    public class Board
    {
        public Spot[,] gameBoardData { get; private set; }
        public Tile[] tileData { get; private set; }

        public void InitializeBoard()
        {
            this.gameBoardData = new Spot[4, 4];

            for (int row = 0; row < 4; row++)
            {
                for (int column = 0; column < 4; column++)
                {
                    this.gameBoardData[row, column] = new Spot();
                    this.gameBoardData[row, column].PieceState = 0;
                }
            }

            Tile tile1 = new Tile(new Spot[4] { gameBoardData[0, 0], gameBoardData[0, 1], gameBoardData[1, 1], gameBoardData[1, 0] });
            Tile tile2 = new Tile(new Spot[4] { gameBoardData[0, 2], gameBoardData[0, 3], gameBoardData[1, 3], gameBoardData[2, 2] });
            Tile tile3 = new Tile(new Spot[4] { gameBoardData[2, 0], gameBoardData[2, 1], gameBoardData[3, 1], gameBoardData[3, 0] });
            Tile tile4 = new Tile(new Spot[4] { gameBoardData[2, 2], gameBoardData[2, 3], gameBoardData[3, 3], gameBoardData[3, 2] });
            this.tileData = new Tile[4] { tile1, tile2, tile3, tile4 };


            tileData[0].Spots[0].PieceState = 25;
            if (gameBoardData[0, 0].PieceState == 25)
            {
                Console.WriteLine("Changes Reflected");
                Console.Read();
            }
        }
    }

    public class Spot
    {
        public int PieceState { get; set; }
    }

    public class Tile
    {
        public Spot[] Spots;
        public Tile(Spot[] spots)
        {
            Spots = spots;
        }
    }
}

Answer 2

注意“new”关键字，您在

new Tile( new Spot[4] { gameBoardData[0, 0], gameBoardData[0, 1], gameBoardData[1, 1], gameBoardData[1, 0] });

这样，您就可以使用gameBoardData的数据创建一个新的Tile对象。因为它是一个新对象，所以它不包含对原始对象的引用。

您想要做的是：

var gameBoardData_1 = new Spot[4, 4];

var tile1 = new Tile(gameBoardData_1);

在内部，你只需将它添加到你正在使用的任何容器中，例如：

m_BoardList.Add(gameBoardData_1);