从2个来源拉取信息并计数

Question

我被要求在工作中创建一个系统，记录通过我们的VoIP系统拨打和接收的电话数量。如果我能够改变数据源的结构，我可能已经做到了这一点，但在这种情况下，我不被允许改变它，这现在取决于我向比我更专业的人请教。

数据源1(使用MSSQL) -这将记录登录到我们的intranet的用户及其扩展名：

+-------+----------------+--------------+---------------------+
| ID    | USERNAME       | EXTENSION    | LOGGEDIN            |
+-------+----------------+--------------+---------------------+
| 1     | JESS           | 101          | 2014-11-10 12:00:00 |
+-------+----------------+--------------+---------------------+
| 2     | SARAH          | 203          | 2014-11-10 12:21:00 |
+-------+----------------+--------------+---------------------+
| 3     | FERN           | 124          | 2014-11-10 12:21:31 |
+-------+----------------+--------------+---------------------+
| 4     | SARAH          | 101          | 2014-11-10 13:12:00 |
+-------+----------------+--------------+---------------------+

数据源2(使用MySQL) -数据源2包含使用VoIP系统发出和接收的所有调用

+-------+----------------+---------------+---------------------+
| ID    | SRC            | DST           | TIME                |
+-------+----------------+---------------+---------------------+
| 1     | 101            | 02035654684   | 2014-11-10 12:01:00 |
+-------+----------------+---------------+---------------------+
| 2     | 203            | 02087816328   | 2014-11-10 12:22:00 |
+-------+----------------+---------------+---------------------+
| 3     | 124            | 02078939273   | 2014-11-10 12:23:31 |
+-------+----------------+---------------+---------------------+
| 4     | 101            | 04672738782   | 2014-11-10 13:15:00 |
+-------+----------------+---------------+---------------------+
| 5     | 07863522413    | 101           | 2014-11-10 13:21:00 |
+-------+----------------+---------------+---------------------+
| 6     | 02076352423    | 203           | 2014-11-10 13:25:31 |
+-------+----------------+---------------+---------------------+
| 7     | 07836325726    | 101           | 2014-11-10 13:56:00 |
+-------+----------------+---------------+---------------------+

这是我希望能够打印的内容：

+-------+----------------+--------------+--------------+-------------+
| ID    | USERNAME       | INCOMING     | OUTGOING     | TOTAL       |
+-------+----------------+--------------+--------------+-------------+
| 1     | JESS           | 0            | 1            | 1           |
+-------+----------------+--------------+--------------+-------------+
| 2     | SARAH          | 2            | 2            | 4           |
+-------+----------------+--------------+--------------+-------------+
| 3     | FERN           | 0            | 1            | 1           |
+-------+----------------+--------------+--------------+-------------+

从上面的表格中可以看到，Sarah从分机203开始，然后在Jess离开后登录到101。她在203登录时进行了1次呼叫，在101登录时进行了1次呼叫。她还在登录分机101时接听了2个呼叫。

我将在这个项目中使用PHP。理想情况下，我希望按总降序对上面的表进行排序，但我相信，一旦我有了构建块，我就可以自己解决这个问题。

提前感谢您在这方面能提供的任何帮助。

注意:我曾考虑创建一个临时表来拉取信息，但我已经被告知这不是一个好主意，因为查询的执行时间以及我需要拉取信息的频率。该脚本将每10秒运行一次，因此我使用的任何查询都需要非常精简。

Answer 1

SELECT
   u.ID,
   u.USERNAME,
   coalesce(tSRC.INCOMING,0) as INCOMING,
   coalesce(tDST.OUTGOING,0) as OUTGOING,
   (coalesce(tSRC.INCOMING,0)+coalesce(tDST.OUTGOING,0)) as total
FROM
table1 u
LEFT JOIN (
   SELECT a.SRC as ext , count(a.ID) as INCOMING
   FROM table2 a WHERE CHAR_LENGTH(a.SRC)=3 GROUP BY a.SRC
   ) tSRC ON tSRC.ext = u.EXTENSION
LEFT JOIN (
   SELECT b.SRC as ext , count(b.ID) as OUTGOING
   FROM table2 b WHERE CHAR_LENGTH(b.DST)=3 GROUP BY b.DST
   ) tDST ON tDST.ext = u.EXTENSION

编辑:更好的版本：

SELECT
   u.ID,
   u.USERNAME,
   u.EXTENSION,
   COUNT(distinct a.ID) as INCOMING,
   COUNT(distinct b.ID) as OUTGOING,
   (COUNT(distinct a.ID)+COUNT(distinct b.ID)) as TOTAL
FROM
table1 u
LEFT JOIN table2 a ON u.EXTENSION=a.SRC
LEFT JOIN table2 b ON u.EXTENSION=b.DST
GROUP BY u.EXTENSION 

Answer 2

$q1="SELECT USERNAME, EXTENSION, unix_timestamp(LOGGEDIN) as t FROM table1 WHERE 1 ORDER BY EXTENSION,LOGGEDIN";

$q2="
(SELECT SRC-0 as EXTENSION, 0 as side, unix_timestamp(`TIME`) as t FROM table2 WHERE CHAR_LENGTH(SRC)=3 )
UNION
(SELECT DST-0 as EXTENSION, 1 as side, unix_timestamp(`TIME`) as t FROM table2 WHERE CHAR_LENGTH(DST)=3 )
ORDER BY EXTENSION, t";


$r1 = $db1->query($q1);
$r2 = $db2->query($q2);

$x1 = $r1->fetch_object();
$x2 = $r2->fetch_object();

$users = array();

$future_x1 = $r1->fetch_object();

while($x1 && $x2)
{
    if( $x1->EXTENSION < $x2->EXTENSION )
    {
        $x1=$future_x1 ;
        $future_x1=$r1->fetch_object();
    }
    elseif( $x1->EXTENSION > $x2->EXTENSION )
    {
        $x2 = $r2->fetch_object();
    }
    elseif( $future_x1 && $future_x1->EXTENSION == $x1->EXTENSION && $x2->t >= $future_x1->t )
    {
        $x1=$future_x1 ;
        $future_x1=$r1->fetch_object();
    }
    else
    {
        @$users[$x1->USERNAME][$x2->side]++;
        $x2 = $r2->fetch_object();
    }
}

print_r($users);

这个解决方案假设您能够从PHP连接到这两个数据库，并且可以从两个表中读取几乎所有的行，并保存一个大小等于用户名数量的数组。