在开始代码之前测试LED

Question

找不到我要找的东西。

我写了以下代码：

    /*
  Traffic Lights
  Turns on an LED on in a predetermined sequence - Red, Red Amber, Green, Amber, Red.

  This example code is in the public domain.
 */

// determine the colours and the pins that they are connected to
int green = 12; //green
int amber = 8; //amber
int red = 4; //red

// the setup routine runs once when you press reset:
void setup() 
{                
  // initialize the digital pins as an output.
  pinMode(green, OUTPUT); 
  pinMode(amber, OUTPUT);
  pinMode(red, OUTPUT);
}

// the loop routine runs over and over again forever:
void loop() {
  digitalWrite(red, HIGH); //red on
  delay(1250);
  digitalWrite(amber, HIGH); //red amber on
  delay(1250);
  digitalWrite(red, LOW);
  digitalWrite(amber, LOW); //red amber off
  delay(250);
  digitalWrite(green, HIGH); //green on
  delay(1250);
  digitalWrite(green, LOW); //green off
  delay(250);
  digitalWrite(amber, HIGH); //amber on
  delay(1250);
  digitalWrite(amber, LOW); //amber off
  delay(250);
  digitalWrite(red, HIGH); //red on
  delay(1250);


}

我非常喜欢Arduino；我的一个开发朋友正试图让我在代码工作之前‘测试’所有的东西( n00b方法)，我的想法是在开始的时候同时打开所有的灯；例如，用一个小'digitalWrite(green, HIGH);就可以很简单地做到这一点。但是，我不希望它循环，我只想让它们只打开一次，持续大约2秒，以表明它们正在工作，然后进入循环。

有人能帮上忙吗？

Answer 1

只要在你的设置函数中就可以了！请记住，当Arduino通电(或重置)时，setup只运行一次，然后循环函数将被调用，直到设备断电。

我会尝试下面的代码片段：

void setup() 
{                
  // initialize the digital pins as an output.
  pinMode(green, OUTPUT); 
  pinMode(amber, OUTPUT);
  pinMode(red, OUTPUT);
  //Turn the pins on to check your wiring
  digitalWrite(green, HIGH);
  digitalWrite(amber, HIGH);
  digitalWrite(red, HIGH);
  delay(1000);
  digitalWrite(green, LOW);
  digitalWrite(amber, LOW);
  digitalWrite(red, LOW);
}

编辑:在ifdef中包含调试代码可能也是值得的：

#ifdef DEBUG
...
#endif 

编辑:澄清(回复评论)：

#ifdef DEBUG
  digitalWrite(green, HIGH);
  digitalWrite(amber, HIGH);
  digitalWrite(red, HIGH);
  delay(1000);
  digitalWrite(green, LOW);
  digitalWrite(amber, LOW);
  digitalWrite(red, LOW);
#endif 

这样，您就可以保留调试代码，并在不再调试时将其“关闭”。