PHP: Longpolling - $current_row & $latest_row

Question

在我的JavaScript长轮询脚本中，我调用msgsrv.php来回显屏幕上还没有出现的num_rows。下面是正在运行的JavaScript：

<script type="text/javascript" charset="utf-8">
function addmsg(type, msg){
    /* Simple helper to add a div.
    type is the name of a CSS class (old/new/error).
    msg is the contents of the div */
    $("#notiWrap.notiZero").html(
        "<div id='notiZero "+ type +"'>"+ msg +"</div>"
    );
}

function waitForMsg(){
    /* This requests the url "msgsrv.php"
    When it complete (or errors)*/
    $.ajax({
        type: "GET",
        url: "http://mediahood.net/widgets/txtr/inc/msgsrv.php",

        async: true, /* If set to non-async, browser shows page as "Loading.."*/
        cache: false,
        timeout:50000, /* Timeout in ms */

        success: function(data){ /* called when request to barge.php completes */
            addmsg("notiMsg", data); /* Add response to a .msg div (with the "new" class)*/
            setTimeout(
                waitForMsg, /* Request next message */
                1000 /* ..after 1 seconds */

            );
        },
    });
};
$(document).ready(function(){
    waitForMsg(); /* Start the inital request */

});
</script>

但是，msgsrv.php知道数据库中实际的最新行，但它现在不知道加载到页面上的最新行的id。$num_rows工作；$loaded_rows失败。$loaded_rows会失败，因为当JS调用msgsrv.php时，它会重置为数据库的实际num_rows。我需要PHP来读取页面上的$loaded_rows，而不是数据库中的，因为我已经知道如何查询最新的行。

这是我的msgsrv.php：

<?php
/* Send a string after a random number of seconds (2-10) */
sleep(2);

include('/home/alimix/public_html/include/conn.php');

/* Variables */
$nr = mysql_query("SELECT * FROM txtr");
while(mysql_fetch_array($nr))
{$nowrecent =  mysql_num_rows($nr);}

$mr = mysql_query("SELECT * FROM txtr ");
for( $i=0; $i < 1; $i++ )
{$mostrecent = "$nowrecent";}
/* $mostrecent shouldn't equal $nowrecent if new rows aren't loaded*/
    $minus = $nowrecent - $mostrecent;

        if ($minus > 0) {
            //echo $nowrecent;
            echo $minus;
            //echo $mostrecent;
        }
        elseif($minus < 1) {
            echo "nr".$nowrecent."";
            echo " ";
            echo "mr".$mostrecent."";
        }


?>

Answer 1

而不是提供这个：

    url: "http://mediahood.net/widgets/txtr/inc/msgsrv.php",

输入以下内容：

    url: "http://mediahood.net/widgets/txtr/inc/msgsrv.php",
    data: {
      lastID: mylastID
    },

每次获得一行时，将mylastID设置为新的最新ID (并确保mylastID在AJAX调用的范围内)。就是这样，你可以使用$_GET‘’lastID‘来恢复这个值！