通过艰苦的方式学习Python 36代码效率

Question

大家好，我正在学习Zed Shaw的“以艰难的方式学习Python”这本书，我已经完成了练习36，我们使用循环和if语句从头开始修改我们自己的游戏。

我的游戏已经结束了，它正在运行，但是代码本身看起来是如此的混乱和低效。主要的问题是试图获得用户的选择，并且必须为相同的单词重写相同的代码，但使用大写字母，例如：

    def puzzle1():
print "\"A cat had three kittens: January,March and May. What was the mother's name.\""

choice = raw_input("Mother's name?: ")
if "What" in choice:
    print "You are correct, the door opens."
    door2()
elif "what" in choice:
    print "You are correct, the door opens."
    door2()
elif "WHAT" in choice:
    print "You are correct, the door opens."
    door2()
elif "mother" in choice:
    print "Haha funny... but wrong."
    puzzle1()
else:
    print "You are not correct, try again."
    puzzle1()

我想知道是否有一种方法可以将所有这些选择放在一行中，如果还有其他我可以做得更有效率的事情，请告诉我。对于这个愚蠢的问题，我很抱歉，我是编程新手。

Answer 1

使用str.lower并删除多个if/elif for what。

choice = raw_input("Mother's name?: ").lower()
if "what" in choice:
    print "You are correct, the door opens."
    door2()
elif "mother" in choice:
    print "Haha funny... but wrong."
    puzzle1()
else:
    print "You are not correct, try again."
    puzzle1()

我还会循环，而不是重复调用puzzle1，如下所示：

while True:
    choice = raw_input("Mother's name?: ").lower()
    if "what" in choice:
        print "You are correct, the door opens."
        return door2()
    elif "mother" in choice:
        print "Haha funny... but wrong."
    else:
        print "You are not correct, try again."