IF语句简化

Question

如何针对一个值实现多个检查？我觉得我有点傻了.

我想要实现的是：

if(basename($_SERVER['SCRIPT_NAME']) != ("1.php" || "2.php" || "3.php"){
    header('Location: elsewhere.php'); 
}

而不是：

if(basename($_SERVER['SCRIPT_NAME']) != "1.php" && basename($_SERVER['SCRIPT_NAME']) != "2.php" && basename($_SERVER['SCRIPT_NAME']) != "3.php" && basename($_SERVER['SCRIPT_NAME']) != "4.php"){
    header('Location: elsewhere.php'); 
}

我已经写了几次了，但我显然是在舔窗口。

提前感谢！

Answer 1

你可以写

$files = array("1.php", "2.php", "3.php", "4.php");//so on

if(!in_array(basename($_SERVER['SCRIPT_NAME']), $files)){
    header('Location: elsewhere.php'); 
}

是的，另一种方法是(比上面的方法快一点)

if(array_diff((array)(basename($_SERVER['SCRIPT_NAME'])),array("1.php", "2.php", "3.php", "4.php")))
{
 header('Location: elsewhere.php'); 
}