当def语句提供特定结果时停止Python程序

Question

我正在尝试在“用Python发明你自己的游戏”一书中创建一个基于龙王国游戏的任务。原版允许做出一个选择，并使用函数来设置这些选择。我试图允许两个不同的选择，但不知道如何在第一个选择后停止任务，如果def语句给出了一个特定的结果，即。如果第一个选择是错误的选择，则用户不能进行第二个选择。任何帮助都将不胜感激。谢谢。

import random
import time

def displayIntro():
    #introduction

def chooseDoor():
    #user chooses door

def checkDoor(chosenDoor):
    #checks user choice against random number

    if chosenDoor == str(friendlyDoor):
        #various good stuff happens
    else:
        #bad stuff happens

    #at this point I would like to go back to the option to play again if they have chosen the wrong door
    #but I can't make it work by putting a break here as it goes on to the next def statement (chooseBox)
    #this is where the original game finished

def chooseBox():
#user chooses a box but only if they made the correct choice above

def checkBox(chosenBox):
#checks user choice against random number and good or bad stuff happens

playAgain = 'yes'
while playAgain == 'yes' or playAgain == 'y':

displayIntro()

doorNumber = chooseDoor()

checkDoor(doorNumber)

boxNumber = chooseBox()

checkBox(boxNumber)

#play again option

Answer 1

如果选择了友好的门，则checkDoor()函数应返回True，否则返回False。然后，在主循环中修改

checkDoor()

至

if not checkDoor():
    continue

这样，玩家选择了一个不友好的门，函数返回False，"continue“语句将程序重置为while循环的下一次执行。否则，它将继续执行chooseBox()