将JSON数据(Twitter (Temboo))从Processing发送到Arduino

Question

我正在做一个学生项目，并试图将JSON数据(基于推特标签'#tune')从Processing发送到Arduino，但方法'myPort.write(status);‘不适用于JSON，我在网上四处寻找，但不确定要使用什么命令--我走对了路吗？代码如下：

处理中：

import processing.serial.*;  //Serial connection for Arduino
import java.lang.reflect.Method;
import com.temboo.core.*;  // Temboo library
import com.temboo.Library.Twitter.Search.*;  // Temboo Twitter search library

// Create a session using your Temboo account application details
TembooSession session = new TembooSession("MYUSERNAME", "MYTEMBOOAPPNAME", "MYTEMBOOCODE");

// Setup objects
Serial myPort;  // Create object from Serial class
int portNo = 7;  // Define portNo as int
int baudRate = 9600;  // Define baudRate as int

void setup() {
  // Run the Tweets Choreo function
  runTweetsChoreo();
  String portName = Serial.list()[portNo]; // Setup String for port ([7] is the port number for my machine)
  myPort = new Serial(this, portName, baudRate);  // Setting up serial port
}

void runTweetsChoreo() {
  // Create the Choreo object using your Temboo session
  Tweets tweetsChoreo = new Tweets(session);

  // Set credential
  tweetsChoreo.setCredential("ArduinoUkulele");

  // Set inputs

  // Run the Choreo and store the results
  TweetsResultSet tweetsResults = tweetsChoreo.run();

  // retrieve the results as JSON
  JSONObject results = parseJSONObject(tweetsResults.getResponse());

  // retrieve the statuses from the results
  JSONArray statuses = results.getJSONArray("statuses");

  // loop through the statuses
  for (int i = 0; i < statuses.size(); i++){
    JSONObject status = statuses.getJSONObject(i);
    println(status.getString("text"));
    println(" -- -- -- -- -- -- -- -- -- -- -- -- -- -- ");
    myPort.write(status);  // THIS IS THE CODE NOT WORKING WITH JSON
  }
}

Arduino：

char val; // Data received from the serial port
int ledPin = 13; // Set the pin to digital I/O 13

void setup(){
  pinMode(ledPin, OUTPUT); // Set pin as OUTPUT
  Serial.begin(9600); // Start serial communication at 9600 bps
}

void loop(){
  if (Serial.available()) { // If data is available to read,
    val = Serial.read(); // read it and store it in val
    Serial.println(val);
    delay(10); // Wait 10 milliseconds for next reading
  }
}

我确信我只是在寻找某个特定的命令--一旦我收到数据，我只需要根据接收到的新标签打开LED即可。任何帮助都将不胜感激！

干杯

亚瑟

Answer 1

write()方法不能将JSONObject作为输入，只能接受byte[]和String。但是您已经拥有了所需的一切:只需使用上面两行所做的那样使用getString()方法(使用适当的键字符串，您应该知道您在JSON之上使用的API )：

 myPort.write(status.getString("text"));