PHP -文本匹配

Question

我目前正在尝试找出两个字符串中匹配的单词的百分比

其想法是，将一个字符串与另一个字符串进行匹配，并获得它们之间的相似度百分比。

我现在有一个粗略的想法，我想知道我是否可以得到一些帮助，这个想法是将每个字符串转换为一个数组，您可以逐个迭代列表，如果匹配，则将1添加到$matches，如果不匹配，则添加0

<?php>
$originalText = "The quick brown fox jumps over the lazy dog";
$comparisonText = "The quick red fox leaps over the sleeping dog";
//to get a count the number of words we are trying to match
$strNum = str_word_count($originalText);

$arroriginalText = explode(" ", $originalText);
$arrcomparisonText = explode(" ", $comparisonText);

//THIS IS WHERE I'M STUCK
//creating some form of a loop to go through the array of strings

if (preg_match("*word from $arroriginalText*, *word from $arrcomparisonText*", $matches)) {
//not fully understanding what to put here
}

//i'm bad at maths
$strNum - $matches = $percentageFind
$percentageFind / $strNum = $decimal
$decimal * 100 = $theAnswer
?>

我不确定我是否已经清楚地表达了我的想法，但如果有任何帮助，我将非常感激。

Answer 1

$matches = 0;

if( empty( $arroriginalText ) ) {
  echo 'Empty';
  die();
}

for( $n = 0; $n < count( $arroriginalText ); $n++ ) {
  if( $arrcomparisonText[$n] === $arroriginalText[$n] ) {
     $matches++;
  }
}

$percentage = 100 * $matches / count( $arroriginalText );

或者更好(未测试)

$percentage = count( array_diff( $arroriginalText, $arrcomparisonText ) ) / count( $arroriginalText );