有人知道思科TelePresence服务器API4.0(2.8)

Question

现在，我有一个Java程序，我想用它来启动网真服务器。代码如下：

public static XmlRpcClient getMCUClient() throws MalformedURLException{
    Lock lock = new ReentrantLock();
    lock.lock();
    try {
        XmlRpcClient client = new XmlRpcClient("https://10.0.0.53/RPC2", true);
        return client;
    } finally {
        lock.unlock();
    }
}

我使用以下代码来创建一个会议：

XmlRpcClient client = XMLClientFactory.getMCUClient();

List<Conference> list = new ArrayList<Conference>();
conference.setAuthenticationUser("admin");
conference.setAuthenticationPassword("password");
conference.setConferenceName("conference_eg");
list.add(conference);

client.invoke("conference.create", list);

我想知道这是否正确，因为没有环境可供我测试。

Answer 1

结合使用Spring和CXF。这很简单，而且很快：

SchedulingAPI13ServiceTest-context.xml：

<jaxws:client address="http://10.66.73.77:8080/ctxapi/api/v1_3/sched"
              id="client" 
              xmlns:s="http://sched.api.ctc.txbu.cisco.com"
              serviceName="s:SchedulingAPI_V1_3Service"
              endpointName="s:SchedulingAPI_V1_3Port"
              wsdlLocation="http://10.66.73.77:8080/ctxapi/api/v1_3/sched?wsdl"
              serviceClass="com.cisco.txbu.ctc.api.sched.ISchedulingAPI"
              username="foo"
              password="bar" >
</jaxws:client>

JUnit测试：

@ContextConfiguration
@RunWith(SpringJUnit4ClassRunner.class)
public class SchedulingAPI13ServiceTest {

    @Autowired
    ISchedulingAPI port;

    @Test
    public void requestResponseTest() throws Exception {
        GetServiceProvidersResult serviceProviders = port.getServiceProviders("(name sw Enterprise)");

    }