带有祖先宝石的Message_controller

Question

对于这个新手问题，我很抱歉，但是，在我的Messages控制器中引用message#new操作时，我得到了以下错误：

ActiveRecord::RecordNotFound (找不到没有ID的用户)：app/controllers/messages_Controler.rb:18:in` `new‘

@recipient = User.find(params[:user_id])

当我试图回复用户收件箱(index.html.erb)中收到的消息时，我正在尝试将祖先宝石合并到我的messages_controller中。据我所知，目前没有ID被传递，但有人遇到过类似的问题吗？代码如下：

class MessagesController < ApplicationController

  def index
    @messages = current_user.to_messages
  end

  def outbox
    type = (params[:type] && params[:type] == "sent" ) ? "from_messages" : "to_messages"
    @messages = current_user.from_messages
  end

  def show
    @message = Message.find params[:id]
  end

  def new
    @message = Message.new(:parent_id => params[:parent_id])
    @recipient = User.find(params[:user_id])
  end

  def create
    @message = Message.new message_params
    @message.sender_id = current_user.id
    if @message.save
      flash[:success] = "Your message has been sent!"
      redirect_to users_path
    else
      flash[:failure] = "Please try again."
      redirect_to users_path
    end
  end

  def destroy
    @message = Message.find(params[:id])
    @message.destroy
    redirect_to messages_path
  end

  private

  def message_params
    params.require(:message).permit(:content, :sender_id, :recipient_id, :parent_id)
  end

end

show.html.erb (视图)

From: <%= link_to @message.recipient.first_name + " " + @message.recipient.last_name, user_path(@message.recipient.id) %>,
To: <%= @message.sender.first_name + " " + @message.sender.last_name %>, 
Message: <%= @message.content %>

<% if @message.recipient_id == current_user.id %>
  <%= link_to "Reply", new_message_path(:parent_id => @message) %>
<% end %>

已开始在2014-09-27 15:41:18 -0400获取127.0.0.1的“/messages/new? MessagesController#new _id=19”，作为超文本标记语言参数：{"parent_id"=>"19"} Message Load (0.1ms) SELECT "messages".* FROM "messages“WHERE "messages"."id”=？限制1 ["id"，19]在11毫秒内未找到已完成的404

ActiveRecord::RecordNotFound (找不到没有ID的用户)：app/controllers/messages_Controler.rb:18:in` `new‘

呈现的/Users/sikendersingh/.rvm/gems/ruby-2.1.2/gems/actionpack-4.1.4/lib/action_dispatch/middleware/templates/rescues/_source.erb (0.5ms)呈现的/Users/sikendersingh/.rvm/gems/ruby-2.1.2/gems/actionpack-4.1.4/lib/action_dispatch/middleware/templates/rescues/_trace.html.erb (1.0ms)呈现/Users/sikendersingh/.rvm/gems/ruby-2.1救援/布局内的.2/gems/actionpack-4.1.4/lib/action_dispatch/middleware/templates/rescues/_request_and_response.html.erb (1.1ms)渲染/Users/sikendersingh/.rvm/gems/ruby-2.1.2/gems/actionpack-4.1.4/lib/action_dispatch/middleware/templates/rescues/diagnostics.erb (13.8ms)

Answer 1

我不确定收件人/发件人的问题，但我认为从您的观点来看，您只需要将user_id作为一个参数传递即可。因此，link_to将变成：<%= link_to "Reply", new_message_path(:parent_id => @message, :user_id => @message.recipient_id) %>。这将使其在新操作中可用。