我是Mysql查询的新手。
我有两个表(tbl1,tbl2)
我需要用start_time升序连接这两个表,并过滤date和emp_id
此处的表字段不同(start-time -> in-time、end-time -> out-time)
tbl-1:
id start-time end-time date emp_id
1 09:00:00 09:00:59 2014-05-14 1
2 10:00:00 10:00:59 2014-05-14 1
3 12:00:00 12:00:59 2014-05-14 1
4 14:00:00 14:00:59 2014-05-14 1
5 16:00:00 17:00:59 2014-05-13 1
tbl-2:
id in-time out-time date emp_id
1 11:00:00 11:00:59 2014-05-14 1
2 13:00:00 13:00:59 2014-05-14 1
3 15:00:00 15:00:59 2014-05-14 1
4 18:00:00 19:00:59 2014-05-14 2
5 20:00:00 20:00:59 2014-05-15 1
filterd by date, emp_id ordered by date
result-tbl:
id start-time end-time date emp_id
1 09:00:00 09:00:59 2014-05-14 1
2 10:00:00 10:00:59 2014-05-14 1
3 11:00:00 11:00:59 2014-05-14 1
4 12:00:00 12:00:59 2014-05-14 1
5 13:00:00 13:00:59 2014-05-14 1
6 14:00:00 14:00:59 2014-05-14 1
7 15:00:00 15:00:59 2014-05-14 1发布于 2014-05-14 19:55:58
我不认为你想要加入。我认为您需要一个union all以及一个重新分配id的方法。类似于:
select (@rn := @rn + 1) as id, intime as starttime, outtime as outtime, emp_id
from ((select * from tbl1)
union all
(select * from tbl2)
) t cross join
(select @rn := 0) var
where emp_id = 1 and
intime <= '18:00:00'
order by intime;发布于 2014-05-14 19:58:36
你想有一个记录的联盟吗?
select in_time, out_time, date, emp_id from tbl1
union all
select star_time, end_time, date, emp_id from tbl2
order by in_time, out_time, date, emp_id;编辑:加过滤器:
select in_time, out_time, date, emp_id from tbl1
where emp_id = 1 and date = '2014-05-14'
union all
select star_time, end_time, date, emp_id from tbl2
where emp_id = 1 and date = '2014-05-14'
order by in_time, out_time;发布于 2014-05-14 19:59:16
这可能会解决你的问题。
select *
from (
select id,star_time,end_time,date,emp_id
from tbl1
where [date-filter-condition]
union all
select id,in_time as star_time,out_time end_time,date,emp_id
from tbl2
where [date-filter-condition]
) tmp
where tmp.date==[some-date-filter] and tmp.emp_id=[some-emp-id-filter]
order by tmp.datehttps://stackoverflow.com/questions/23653930
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