需要纠正台球游戏中球的"friction"/travel距离，在处理中

Question

嘿，伙计们，我正在构建这个简单的台球游戏，我希望这个黑球，标记为bBall，和白色球，标记为wBall，走的距离相同，并且不会更远。也就是说，如果白球在击中黑球之前移动了20个像素，我希望黑球移动20个像素，然后停止。我该如何着手实现这一点呢？谢谢你们的帮助。

处理2.0.3

ball wBall, bBall;
int click;
String msg;
Boolean moving = false;
float difx, dify;
float cdistance;
int steps = 40;
void setup(){
   click=0;
   size(800,400);
   background(16,77,27);
   wBall = new ball(35,#ffffff);
   bBall = new ball(35,#000000);
   msg="";
}

void mouseClicked(){
  if(!moving){
 click++; 
  }
}

void draw(){
  background(16,77,27);
  String msg;
  fill(0,0,0);
 ellipse(15,15,30,30); 
 ellipse(785,15,30,30);
 ellipse(15,385,30,30);
 ellipse(785,385,30,30);
 ellipse(410,15,30,30);
 ellipse(410,385,30,30);
 msg="the count is "+click;
 println("the count is "+click);
 //Moving Balls\\
 fill(255,255,255);
 noStroke();  

 if(click==0){
       wBall.xpos=mouseX;
       wBall.ypos=mouseY;
 }else if(click==1){
       bBall.xpos=mouseX;
       bBall.ypos=mouseY;
 }else if(click==2){
       difx = wBall.xpos-bBall.xpos;
       dify = wBall.ypos-bBall.ypos;
 }
  else if(click==3){
 cdistance = dist(wBall.xpos,wBall.ypos,bBall.xpos,bBall.ypos);
   if (cdistance>bBall.ballDiam/2){
       moving = true;
       wBall.xpos-=difx/steps;
       wBall.ypos-=dify/steps;
   }
   else{
      moving = false;
      click=4;
      println("click"+click);
   }
 }else if(click==4){
  if(cdistance<bBall.ballDiam){
    moving = true;
    bBall.xpos-=difx/steps;
    bBall.ypos-=dify/steps; 
  }
 }
 wBall.update();
 bBall.update();
}

class ball{
  float xpos, ypos;
  color myColor;
  int ballDiam;
  boolean visible = true;
  ball(int tempdiam, color tempColor){
    myColor=tempColor;
    ballDiam=tempdiam;
  }

   void update(){
   if(visible){
    fill(myColor);
    ellipse(xpos,ypos,ballDiam,ballDiam);
   }
  }
}
  void keyPressed(){
   if (key =='c'){
    setup();
   } 
}

Answer 1

一种方法是使您的

 else if (click==4) {
    if (cdistance<bBall.ballDiam) {
      moving = true;
      bBall.xpos-=difx/steps;
      bBall.ypos-=dify/steps;
    }
  }

至

 else if (click==4) {
    if (cdistance<bBall.ballDiam) {
      if (dist(wBall.xpos, wBall.ypos, bBall.xpos, bBall.ypos) < sqrt(sq(difx)+sq(dify))) {
        moving = true;
        bBall.xpos-=difx/steps;
        bBall.ypos-=dify/steps;
      }
    }
  }

本质上，只有当球与白色球的距离小于原始差异时，才会移动球。

尽管如此，我还是觉得你正在以一种艰难的方式来处理这件事。也许你可以在游戏中引入速度和加速度(甚至是摩擦力)计算，这样会更有意义……