C++接口继承

Question

如何在C++中进行此派生？(当前示例不起作用)

  struct IB
    {

    };

    struct IDerivedB : public IB
    {

    };

    struct IA
    {
    public:
        virtual IB Foo(const string& type) = 0;
    };

    struct IDerivedA : public IA
    {
    public:
        virtual IDerivedB Foo(const string& type) override = 0;
    };

谢谢!

Answer 1

返回类型协方差仅适用于指针和引用，这应该是可行的：

struct IB
{

};

struct IDerivedB : public IB
{

};

struct IA
{
public:
    virtual IB* BuildPresenter(const string& type) = 0;
};

struct IDerivedA : public IA
{
public:
    virtual IDerivedB* BuildPresenter(const string& type) override = 0;
};