当我点击在div中的小图像时,我想要显示一个大图像。我已经在jQuery上尝试过了,但是不起作用。我哪里做错了?
<script>
$( document ).ready(function() {
$('#imgVieuw').hide();
$('.click').click(function(){
var element = $(this).attr('id');
var element2 = element;
element = "#" + element2;
var bigimg = "#v" + element2;
$('#vincent, element').click(function() {
console.log(element+" "+bigimg);
$('#imgVieuw, bigimg').fadeIn();
});
});
$('#closeButton').click(function() {
$('#imgVieuw, .img').fadeOut();
});
});
</script>
<section id="vincent">
<div class='click' id="img1"><img src="images/vincent/tumb city.png"></div>
<div class='click' id="img2"><img src="images/vincent/tumb city2.png"></div>
<div class='click' id="img3"><img src="images/vincent/tumb eye.png"></div>
<div class='click' id="img4"><img src="images/vincent/tumb island.png"></div>
<div class='click' id="img5"><img src="images/vincent/tumb planet.png"></div>
<div class='click' id="img6"><img src="images/vincent/tumb tiger.png"></div>
<div class='click' id="img7"><img src="images/vincent/tumb white tiger.png"></div>
</section>
<div id="imgVieuw">
<img class="img" id="vimg1" src="images/vincent/city.jpg">
<img class="img" id="vimg2" src="images/vincent/city2.jpg">
<img class="img" id="vimg3" src="images/vincent/eye.jpg">
<img class="img" id="vimg4" src="images/vincent/island.jpg">
<img class="img" id="vimg5" src="images/vincent/planet.jpg">
<img class="img" id="vimg6" src="images/vincent/tiger.jpg">
<img class="img" id="vimg7" src="images/vincent/white tiger.jpg">
</div>你可以在我的演示网页上找到一个例子,然后点击按钮vincent:http://vwdemo.comxa.com/parallax在那里你可以找到我的缩略图。
提前谢谢。
发布于 2014-10-04 22:29:28
你可以大大简化你的代码:
$(document).ready(function () {
$('.click').click(function () {
var bigimg = '#v' + this.id;
$('#imgVieuw').find(bigimg).fadeIn();
});
$('#closeButton').click(function () {
$('#imgVieuw .img').fadeOut();
});
});请注意,$('#imgVieuw, bigimg')没有任何意义,因为它应该类似于$('#imgVieuw').find(bigimg).fadeIn();
此外,您永远不应该在其他单击事件处理程序中绑定单击事件,这样您就会得到绑定到同一元素的一堆处理程序。
演示:http://jsfiddle.net/w0mzhL8a/
https://stackoverflow.com/questions/26193699
复制相似问题