如何在Arduino中获得连续的LED闪光灯？[C/C++]

Question

我有一个简单的Arduino程序，它每5秒将温度传感器的感应值上传到Google电子表格中。这一切都很好。我有3个LED。一个在设置完成时永久亮起，一个在上传数值时闪烁，还有一个在上传完成时亮起3秒。

我的问题是，我不知道如何让引脚3 LED闪烁，而值正在上传。无论我把它放在哪里，它似乎只运行一次，然后继续程序的其余部分。我意识到这是一个非常基本的逻辑问题，但我不能解决它，真的很感谢一些帮助！

下面是主程序。

/* Setup shield-specific #include statements */
#include <SPI.h>
#include <WiFi.h>
#include <WiFiClient.h>
#include <Temboo.h>
#include "TembooArduino.h" // Contains Temboo account information


WiFiClient client;

int numRuns = 1;   // Execution count, so this doesn't run forever
int maxRuns = 3;   // Maximum number of times the Choreo should be executed


void setup() {
  Serial.begin(9600);
  pinMode(A0,INPUT);
  pinMode(4, OUTPUT);
  digitalWrite(4, LOW);
  pinMode(3, OUTPUT);
  digitalWrite(3, LOW);
  pinMode(2, OUTPUT);
  digitalWrite(2, LOW);
  // For debugging, wait until the serial console is connected.
  delay(4000);
  while(!Serial);

  int wifiStatus = WL_IDLE_STATUS;

  // Determine if the WiFi Shield is present.
  Serial.print("\n\nShield:");
  if (WiFi.status() == WL_NO_SHIELD) {
    Serial.println("FAIL");

    // If there's no WiFi shield, stop here.
    while(true);
  }

  Serial.println("OK");

  // Try to connect to the local WiFi network.
  while(wifiStatus != WL_CONNECTED) {
    Serial.print("WiFi:");
    wifiStatus = WiFi.begin(WIFI_SSID, WPA_PASSWORD);

    if (wifiStatus == WL_CONNECTED) {
      Serial.println("OK");
    } else {
      Serial.println("FAIL");
    }
    delay(5000);
  }

  Serial.println("Setup complete.\n");
  digitalWrite(4,HIGH);
}

void loop() {
    if (numRuns <= maxRuns)
      { 
    Serial.println("Running AppendRow - Run #" + String(numRuns++) + "\n");

    int sensorVal = analogRead(A0);

    //two lines to test the sensor value in serial output 
    Serial.print("sensor Value: "); 
    Serial.print(sensorVal);

    float voltage = (sensorVal/1024.0) * 5.0; //testing voltage output in serial 

    Serial.print(", volts "); 
    Serial.print(voltage); 

    float temperature = (voltage - .5) * 100; 

    Serial.print(", temperature in C ");
    Serial.print(temperature);
    Serial.print("\n");

    TembooChoreo AppendRowChoreo(client);


    // Invoke the Temboo client
    AppendRowChoreo.begin();

    // Set Temboo account credentials
    AppendRowChoreo.setAccountName(TEMBOO_ACCOUNT);
    AppendRowChoreo.setAppKeyName(TEMBOO_APP_KEY_NAME);
    AppendRowChoreo.setAppKey(TEMBOO_APP_KEY);

    // Set Choreo inputs
    String UsernameValue = "xxxx";
    AppendRowChoreo.addInput("Username", UsernameValue);
    String PasswordValue = "xxxx";
    AppendRowChoreo.addInput("Password", PasswordValue);
    String RowDataValue = (String)analogRead(A0);
    AppendRowChoreo.addInput("RowData", RowDataValue);
    String SpreadsheetTitleValue = "TempSensor";
    AppendRowChoreo.addInput("SpreadsheetTitle", SpreadsheetTitleValue);

    // Identify the Choreo to run
    AppendRowChoreo.setChoreo("/Library/Google/Spreadsheets/AppendRow");
    // Run the Choreo; when results are available, print them to serial
    AppendRowChoreo.run();
    while(AppendRowChoreo.available()) 
    {
      char c = AppendRowChoreo.read();
      Serial.print(c);
    }
    AppendRowChoreo.close();

    digitalWrite(2, HIGH);
    delay(3000);      
    digitalWrite(2, LOW);

      }

  Serial.println("\nWaiting...\n");
  delay(5000); // wait 5 seconds between AppendRow calls
}

下面是我想要实现的循环

void flash()
{
    digitalWrite(3, HIGH);
    delay(100);
    digitalWrite(3, LOW);
    delay(100);
} 

开始于

TembooChoreo AppendRowChoreo(client);

和结束于

AppendRowChoreo.close();

Answer 1

看一看Timer Library。此库允许您在特定延迟后运行任务，而无需使用delay()函数。

该库是一个使用计时器中断来调度任务的实现。你可以用手做同样的事情。

这里要看到的主要思想是，使用delay()来调度任务通常是浪费的，因为它将处理器锁定为不做任何事情--“忙于等待”。相反，嵌入式程序员需要学习如何使用定时器中断来中断主“线程”来运行任务，而不浪费处理器周期。