如何在android中注销receiver？

Question

我得到了这个错误的东西Leaked Intent Receiver that was originally registered here，但应用程序仍然启动和运行，即使有这个错误的东西，是什么导致了这个错误？这对应用程序有影响吗？

这就是我想要做的：

private void sendSMS(String phoneNumber, String message) {
    String SENT = "SMS_SENT";
    String DELIVERED = "SMS_DELIVERED";

    ArrayList<PendingIntent> sentPendingIntents = new ArrayList<PendingIntent>();
    ArrayList<PendingIntent> deliveredPendingIntents = new ArrayList<PendingIntent>();

    PendingIntent sentPI = PendingIntent.getBroadcast(this, 0, new Intent(
            SENT), 0);

    PendingIntent deliveredPI = PendingIntent.getBroadcast(this, 0,
            new Intent(DELIVERED), 0);
    try {
        SmsManager sms = SmsManager.getDefault();
        ArrayList<String> mSMSMessage = sms.divideMessage(message);
        for (int i = 0; i < mSMSMessage.size(); i++) {
            sentPendingIntents.add(i, sentPI);
            deliveredPendingIntents.add(i, deliveredPI);
        }
        sms.sendMultipartTextMessage(phoneNumber, null, mSMSMessage,
                sentPendingIntents, deliveredPendingIntents);

    } catch (Exception e) {

        e.printStackTrace();
        Toast.makeText(this, "SMS sending failed...", Toast.LENGTH_SHORT)
                .show();
    }

    // ---when the SMS has been sent---
    registerReceiver(new BroadcastReceiver() {
        @Override
        public void onReceive(Context arg0, Intent arg1) {
            switch (getResultCode()) {
            case Activity.RESULT_OK:
                Toast.makeText(getBaseContext(), "SMS sent",
                        Toast.LENGTH_SHORT).show();
                break;
            case SmsManager.RESULT_ERROR_GENERIC_FAILURE:
                Toast.makeText(getBaseContext(), "Generic failure",
                        Toast.LENGTH_SHORT).show();
                break;
            case SmsManager.RESULT_ERROR_NO_SERVICE:
                Toast.makeText(getBaseContext(), "No service",
                        Toast.LENGTH_SHORT).show();
                break;
            case SmsManager.RESULT_ERROR_NULL_PDU:
                Toast.makeText(getBaseContext(), "Null PDU",
                        Toast.LENGTH_SHORT).show();
                break;
            case SmsManager.RESULT_ERROR_RADIO_OFF:
                Toast.makeText(getBaseContext(), "Radio off",
                        Toast.LENGTH_SHORT).show();
                break;
            }
        }
    }, new IntentFilter(SENT));

    // ---when the SMS has been delivered---
    registerReceiver(new BroadcastReceiver() {
        @Override
        public void onReceive(Context arg0, Intent arg1) {
            switch (getResultCode()) {
            case Activity.RESULT_OK:
                Toast.makeText(getBaseContext(), "SMS delivered",
                        Toast.LENGTH_SHORT).show();
                break;
            case Activity.RESULT_CANCELED:
                Toast.makeText(getBaseContext(), "SMS not delivered",
                        Toast.LENGTH_SHORT).show();
                break;
            }
        }
    }, new IntentFilter(DELIVERED));
}

预付tnx ..

Answer 1

• 如果您已在onCreate中注册接收器，则在其onDestroy方法中注销它。
• 如果您已在onResume中注册接收器，则在其onPause方法中注销它。
• 如果您已在onStart中注册接收器，则在其onStop方法中注销它。

Answer 2

这个问题很可能是因为您从中调用sendSMS的Activity已经退出，但这是您将接收器注册为匿名内部类的上下文。您需要取出这些接收器，或者保留对它们的引用并在您的onPause()中注销它们。

Answer 3

由于接收方是在活动内部注册的，而不是在清单中注册的，因此需要取消注册onPause或onStop

 public void onStop() {
        super.onStop();
        if (myReceiver != null) {
            unregisterReceiver(myReceiver);
        }

我忘记提到应该在内部类中创建BroadcastReceiver，比如

  private class myReceiver extends BroadcastReceiver{

        @Override
        public void onReceive(Context context, Intent intent) {
            //Add your code here
        }
    }

希望能有所帮助。