android编程入门

Question

在下面的程序中，当我尝试运行它的获取错误时

textOut = (TextView) findViewById(R.id.tvGetInput);

在这条线上。它在tvGetInput中显示错误。我怎么才能修复它？

package was.thebasics;

import android.app.Activity;
import android.content.Intent;
import android.media.MediaPlayer;
import android.os.Bundle;
import android.view.View;
import android.widget.Button;
import android.widget.EditText;
import android.widget.TextView;


public class mymenu extends Activity {

    TextView textOut;
    EditText GetInput;



    @Override
    protected void onCreate(Bundle savedInstanceState) {
        // TODO Auto-generated method stub
        super.onCreate(savedInstanceState);
        setContentView(R.layout.main);

        textOut = (TextView) findViewById(R.id.tvGetInput);
        GetInput = (EditText) findViewById(R.id.etInput);
        Button ok = (Button) findViewById(R.id.bOK);
        ok.setOnClickListener(new View.OnClickListener() {

            public void onClick(View v) {
                // TODO Auto-generated method stub
                textOut.setText(GetInput.getText());
            }
        });
        // set up the button sound
        final MediaPlayer mpButtonClick = MediaPlayer.create(this, R.raw.button);



        Button bTutorial1 = (Button) findViewById(R.id.tutorial1);
        bTutorial1.setOnClickListener(new View.OnClickListener() {
      public void onClick(View v) {
                // TODO Auto-generated method stub
                startActivity(new Intent("was.thebasics.tutorialOne"));
                mpButtonClick.start();
            }
        });


    }
    }

Answer 1

请签入main.xml文件，Textview id就是这样给出的。

android:id="@+id/tvGetInput"

Answer 2

检查id是否已在gen文件夹下的R.java文件中创建