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社区首页 >问答首页 >如何加速lat-long到SqlGeometry的转换?

如何加速lat-long到SqlGeometry的转换?
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Stack Overflow用户
提问于 2014-11-28 17:26:17
回答 1查看 1.3K关注 0票数 2

我有这个代码,它接受国家的几何形状和一组点,然后它只返回这些国家的点:

代码语言:javascript
复制
public static IEnumerable<Point> RemovePointsOutsideBorders(IEnumerable<Point> points, IEnumerable<Country> countries)
{
    var cc = new List<Point>();

    var SPAT_REF_ID = 4326;
    foreach (var p in points)
    {
            var validText = new SqlChars(new SqlString(string.Format("POINT({0} {1})", p.Longitude, p.Latitude)));
            var geoPoint = SqlGeometry.STPointFromText(validText, SPAT_REF_ID);

        foreach (var c in countries)
        {
            if(c.Polygon.STIntersects(geoPoint))
            {
                cc.Add(p);
                break;
            }
        }
    }

    return cc;
}

目前它相当慢,大约有4000个点,带有两个经纬值,从它到SqlGeometry的转换很慢(大约需要25秒--我需要把它缩短到一两秒):

代码语言:javascript
复制
var s = new SqlChars(new SqlString(string.Format("POINT({0} {1})", p.Longitude, p.Latitude)));
var pGeo = SqlGeometry.STPointFromText(s, SPAT_REF_ID);

这样做只是因为SqlGeometry.Point接受x,y而不是lat,long ...关于如何加快速度,有什么建议吗?

我已经知道可以减少SqlGeometry (c.Polygon)来加快速度,但我无法控制这一点。我所追求的是一种加速从经纬度到SqlGeometry点的转换的方法。

EN

回答 1

Stack Overflow用户

发布于 2014-11-28 23:59:28

这是我最后想出的解决方案,它在半秒内完成了整个过程:

代码语言:javascript
复制
public static IEnumerable<Point> RemovePointsOutsideBorders(IEnumerable<Point> points, IEnumerable<Country> countries)
{
    // join all the country polygons into one (make a stamp)
    var allCountryPolygon = countries.Select(x => x.Polygon).UnionAll();

    // make a single geometry shape from our evenly spaced extent points (cookie dough)
    var pointsGeo = PointsToGeometry(points);

    // do an intersect (stamp country shape over extent based geometry)
    var cookieOfPoints = pointsGeo.STIntersection(allCountryPolygon);

    // how many points left inside? pick them all back out
    for (int n = 1; n <= cookieOfPoints.STNumPoints(); n++)
    {
        var insidePoint = cookieOfPoints.STPointN(n);
        yield return new Point
        {
            Longitude = insidePoint.STX.Value,
            Latitude = insidePoint.STY.Value
        };
    }
}

public static SqlGeometry PointsToGeometry(IEnumerable<Point> points)
{
    var bld = new SqlGeometryBuilder();
    bld.SetSrid(4326);
    bld.BeginGeometry(OpenGisGeometryType.MultiPoint);

    foreach (var p in points)
    {
        bld.BeginGeometry(OpenGisGeometryType.Point);
        bld.BeginFigure(p.Longitude, p.Latitude);
        bld.EndFigure();
        bld.EndGeometry();
    }

    bld.EndGeometry();
    return bld.ConstructedGeometry;
}

public static class ExtensionMethods
{
    /// <summary>
    /// Joins many geometries into one
    /// </summary>
    /// <param name="geometries">geometries to join</param>
    /// <returns>composite geometry</returns>
    public static SqlGeometry UnionAll(this IEnumerable<SqlGeometry> geometries)
    {
        var compositeGeometry = geometries.First();
        foreach (var g in geometries.Skip(1))
        {
            compositeGeometry = compositeGeometry.STUnion(g);
        }
        return compositeGeometry;
    }
}
票数 2
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页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/27185487

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