对于我的项目,我有一个调用助手函数place-search.js的server.js,如下所示。
var express = require('express');
var server = express.Router();
var placeSearch = require("./helpers/place-search");
var obj = "hello";
server.use(function(req, res, next) {
console.log(req.method, req.url);
next();
});
server.post('/', function(req, res) {
/* get the object passed by the client's post request */
obj = req.body;
//console.log("Obj: " + obj);
/* send the confirmation back to the client */
res.status(200).send("body");
placeSearch.placeSearch(obj);
});
module.exports.server = server;
这是我的位置-search.js:
var config = require("./config.js");
var Promise = require('bluebird');
var DistanceMatrix = require("./distance-matrix.js");
var GooglePlaces = Promise.promisifyAll(require("googleplaces"));
var googlePlaces = new GooglePlaces(config.apiKey, config.outputFormat);
var extract = require('./extract.js');
var combination = require('./combination_ver2.js');
var permutation = require('./permutation.js');
function placeSearch(obj) {
console.log("Inside place search!");
/**
* Place search - https://developers.google.com/places/documentation/#PlaceSearchRequests
*/
var arr = [];
var count = 0;
var rad = obj["radius"];
console.log("radius: " + rad);
var loc = obj["location"];
console.log("Location: " + loc);
var mode = obj["mode"];
var params = obj["params"];
/* client's keywords */
var arr;
var ar = [];
for (var i = 0; i < params; i++) {
arr[i] = obj[i];
console.log(arr[i]);
var param = {
location: loc,
radius: rad,
mode: mode,
keyword: arr[i]
};
ar.push(param);
}
console.log("before promises");
var promises = ar.map(function(name) {
return googlePlaces.placeSearch(name, function(response) {
arr.push(response);
console.log(response);
console.log(count++);
//If all responses have been returned
//Find combos and pass to distance-matrix
if (count == ar.length) {
var Matrix = new Array();
var result = new Array();
//to extract only lat and lng from arr.results
//Matrix = extract.extract(arr);
result = combination.combination(arr);
// NOW RESULT IS THE ARRAY OF ALL COMBINATION
// NOW RESULT IS THE ARRAY OF COMBINATIONS OF latlng pairs AND PASS IT TO FRONTEND
/*result.forEach(function(combo, index) {
console.log("combo" + combo)
DistanceMatrix.distanceMatrix(mode, combo, result.length);
});*/
// IF YOU WANT TO SEE PERMUTATION
//permutation.permutation(result);
console.log("combination results: " + result);
}
})
});
}
module.exports.placeSearch = placeSearch;
我的问题是,我不知道如何将结果变量传递回server.js,这样我就可以将该结果用作另一个辅助函数的输入。我无论如何也想不出怎么做这件事。任何帮助都将不胜感激。
发布于 2014-11-21 03:38:17
嗯,我没有看到你的placeSearch函数现在返回任何东西,也没有做任何形式的回调。您的placeSearch函数应该公开一个回调参数,一旦您有了想要发回的答案,就会调用该参数。
然后,您的服务器文件将对该回调执行操作。缩写你的代码,看起来像这样:
server.post('/', function(req, res) {
/* get the object passed by the client's post request */
obj = req.body;
//console.log("Obj: " + obj);
placeSearch.placeSearch(obj, function(error, data){
/* send the data back to the client */
res.status(200).send(data);
});
});为了支持这一点,您的placeSearch函数必须在适当的时候调用它的回调:
function placeSearch(obj, callback){
/* all the stuff you do to assemble your data */
// if (there_is_some_error):
if(err) return cb(err);
// when you have all your data available, no error has occurred
return cb(null, data);
}您可能会注意到的另一件事是,您的ar.map不会像您预期的那样工作。ar.map是一个同步函数,你在里面调用异步代码...不会像你想的那样工作。这篇文章有点长,但是你应该看看npm的async库来管理一个异步请求数组来收集一个组合的结果。
发布于 2014-11-21 03:39:49
使用回调您的代码如下所示:
function placeSearch(obj,callback) {
console.log("Inside place search!");
/**
* Place search - https://developers.google.com/places/documentation/#PlaceSearchRequests
*/
var arr = [];
var count = 0;
var rad = obj["radius"];
console.log("radius: " + rad);
var loc = obj["location"];
console.log("Location: " + loc);
var mode = obj["mode"];
var params = obj["params"];
/* client's keywords */
var arr;
var ar = [];
for (var i = 0; i < params; i++) {
arr[i] = obj[i];
console.log(arr[i]);
var param = {
location: loc,
radius: rad,
mode: mode,
keyword: arr[i]
};
ar.push(param);
}
console.log("before promises");
var promises = ar.map(function(name) {
return googlePlaces.placeSearch(name, function(response) {
arr.push(response);
console.log(response);
console.log(count++);
//If all responses have been returned
//Find combos and pass to distance-matrix
if (count == ar.length) {
var Matrix = new Array();
var result = new Array();
//to extract only lat and lng from arr.results
//Matrix = extract.extract(arr);
result = combination.combination(arr);
// NOW RESULT IS THE ARRAY OF ALL COMBINATION
// NOW RESULT IS THE ARRAY OF COMBINATIONS OF latlng pairs AND PASS IT TO FRONTEND
/*result.forEach(function(combo, index) {
console.log("combo" + combo)
DistanceMatrix.distanceMatrix(mode, combo, result.length);
});*/
// IF YOU WANT TO SEE PERMUTATION
//permutation.permutation(result);
console.log("combination results: " + result);
callback(null,result);
}
})
});
}在server.js中:
server.post('/', function(req, res) {
/* get the object passed by the client's post request */
obj = req.body;
//console.log("Obj: " + obj);
/* send the confirmation back to the client */
res.status(200).send("body");
placeSearch.placeSearch(obj,function(err,result){
if(!err){
console.log(result);
}
})
});发布于 2014-11-21 03:44:05
看起来你在异步操作中遇到了问题。您将需要从您的位置搜索模块return promise。您还需要将来自placeSearch的回调转换为promise。
编辑:已更新,因为googlePlaces.placeSearch不返回promise
placeSearch内幕
function placeSearch(obj) {
//...
var promises = ar.map(function(name) {
var placeDefer = Q.defer();
return googlePlaces.placeSearch(name, function(response) {
placeDefer.resolve(response); // or placeDefer.reject if a failure occurs
});
return placeDefer.promise;
});
return promises;
}在你的路线中:
// I'm going to just assume Q promise library here
var Q = require("q");
server.post('/', function(req, res) {
/* get the object passed by the client's post request */
obj = req.body;
//console.log("Obj: " + obj);
/* send the confirmation back to the client */
res.status(200).send("body");
Q.all(placeSearch.placeSearch(obj))
.spread(function() {
var places = Array.prototype.slice.call(arguments);
// possibly call res.status(200).send("body"); here?
// only if you're trying to use the places in your response
});
});https://stackoverflow.com/questions/27047715
复制相似问题