如何在swift中使用NSURLSession发布JSON数据

Question

我被下面的代码卡住了。如何在post方法中设置参数？

let params:[String:Any] = [
        "email" : usr,
        "userPwd" : pwdCode]

let url = NSURL(string:"http://inspect.dev.cbre.eu/SyncServices/api/jobmanagement/PlusContactAuthentication")
let request = NSMutableURLRequest(URL: url!)
request.setValue("application/json; charset=utf-8", forHTTPHeaderField: "Content-Type")

request.HTTPBody = params<what should do for Json parameter>


let task = NSURLSession.sharedSession().dataTaskWithRequest(request) {
    data, response, error in

    if let httpResponse = response as? NSHTTPURLResponse {
        if httpResponse.statusCode != 200 {
            println("response was not 200: \(response)")
            return
        }
    }
    if error {
        println("error submitting request: \(error)")
        return
    }

    // handle the data of the successful response here
}
task.resume()

Answer 1

如果我没理解错这个问题

var configuration = NSURLSessionConfiguration.defaultSessionConfiguration()
var session = NSURLSession(configuration: configuration)
var usr = "dsdd"
var pwdCode = "dsds"
let params:[String: AnyObject] = [
    "email" : usr,
    "userPwd" : pwdCode ]

let url = NSURL(string:"http://localhost:8300")
let request = NSMutableURLRequest(URL: url!)
request.setValue("application/json; charset=utf-8", forHTTPHeaderField: "Content-Type")
request.HTTPMethod = "POST"
var err: NSError?
request.HTTPBody = NSJSONSerialization.dataWithJSONObject(params, options: NSJSONWritingOptions.allZeros, error: &err)

let task = session.dataTaskWithRequest(request) {
    data, response, error in

    if let httpResponse = response as? NSHTTPURLResponse {
        if httpResponse.statusCode != 200 {
            println("response was not 200: \(response)")
            return
        }
    }
    if (error != nil) {
        println("error submitting request: \(error)")
        return
    }

    // handle the data of the successful response here
    var result = NSJSONSerialization.JSONObjectWithData(data, options: NSJSONReadingOptions.allZeros, error: nil) as? NSDictionary
    println(result)
}
task.resume()

我建议使用AFNetworking。例如，请参阅Posting JSON data using AFNetworking 2.0。

Answer 2

这就是如何设置参数和发送POST请求，使用Alamofire的简单方法。

• Swift 2.2

让URL = NSURL(string："https://SOME_URL/web.send.json")！let mutableURLRequest = NSMutableURLRequest(URL: URL) mutableURLRequest.HTTPMethod = "POST“let参数= ["api_key"："______"，"email_details"："fromname"："______"，" subject”：“这是测试邮件主题”，"from"："support@apple.com"，"content"：“嗨，这是一封测试邮件。”，“NSJSONSerialization.dataWithJSONObject(parameters，”："_________"] do { mutableURLRequest.HTTPBody =尝试收件人选项:NSJSONWritingOptions()} mutableURLRequest.setValue("application/json"，{ // No-op }_________forHTTPHeaderField："Content-Type") Alamofire.request(mutableURLRequest) .responseJSON {打印响应(response.request) //原始URL请求打印(response.response) // URL响应打印(response.data) //服务器数据打印(response.result) //如果让JSON = response.result.value { print("JSON：(JSON)“)} }