获取ido生成的候选列表

Question

是否可以获取列表并将其保存在变量中？我跑步

(ido-completing-read "prompt: " '("one" "two" "three" "four" "five") nil nil "t")

ido生成候选列表{two | three}。我想要这样的东西

(setq my-desired-list (ido-completing-read-silent '("one" "two" "three" "four" "five") nil nil "t"))

执行后my-desired-list的值为("two" "three")。我对ido使用了复杂的设置，它为choices准备了非常特殊的过滤器，我想直接使用结果。

Answer 1

变量‘ido-matches’将包含上次调用ido-completing read时的匹配项。所以这就是你想要的：

(defun ido-completing-read-silent (prompt choices initial-input)
  (ido-completing-read prompt choices nil nil initial-input)
  ido-matches)

(ido-completing-read-silent "prompt: " '("one" "two" "three" "four" "five") "t")
;; ("two" "three")

Answer 2

(defun ido-completing-read-silent (prompt choices initial-input)
  (run-with-timer 0.0001 nil 'exit-minibuffer)
  (ido-completing-read prompt choices nil nil initial-input)
  (mapcar (lambda (x) (flx-propertize x nil)) ido-matches))

(equal (ido-completing-read-silent "prompt: " '("one" "two" "three" "four" "five") "t")
       '("three" "two"))

该解决方案可以用于其他情况，用于不同的交互功能，如ido-completing-read。