Web forms sytax to Razor sytax

Question

我正在做NerdDinner。我想使用Razor sytax而不是Web forms。当我调试项目的时候。它说“模型”没有定义。显示的全部错误如下：

Unhandled exception at line 133, column 9 in http://localhost:52372/Dinner/Create

0x800a1391 - Microsoft JScript runtime error: 'Model' is undefined

它生成了一个名为

Create[dynamic]

这个文件是什么意思，我的Razor语法有什么问题。

提前谢谢。

原始语法

<script src="http://dev.virtualearth.net/mapcontrol/mapcontrol.ashx?v=6.2" type="text/javascript"></script> 
<script src="/Scripts/Map.js" type="text/javascript"></script>  

<div id="theMap"> 
</div>  

<script type="text/javascript">      
$(document).ready(function() {      
var latitude = <%=Model.Latitude%>;    
var longitude = <%=Model.Longitude%>;  

if ((latitude == 0) || (longitude == 0))          
LoadMap();   

else          
LoadMap(latitude, longitude, mapLoaded); 
}); 

function mapLoaded() {      
var title = "<%=Html.Encode(Model.Title) %>";    
var address = "<%=Html.Encode(Model.Address) %>";      
LoadPin(center, title, address);  
map.SetZoomLevel(14); 
}  
</script>

Razor语法

@model NerdDinner.Models.Dinner

<script src="http://dev.virtualearth.net/mapcontrol/mapcontrol.ashx?v=6.2" type="text/javascript"></script> 
<script src="/Scripts/Map.js" type="text/javascript"></script> 

<div id="theMap">
    </div>

<script type="text/javascript">

    $(document).ready(function () {

        var latitude = Model.Latitude;
        var longitude =Model.Longitude;

        if ((latitude == 0) || (longitude == 0))
            LoadMap();
        else
            LoadMap(latitude, longitude, mapLoad);    
    });

    function mapLoad()
    {

        var title = "@Html.Encode(Model.Title)"
        var address = "@Html.Encode(Model.Address)"

        LoadPin(center,title,address);
        map.setZoomLevel(14);
    }

    </script>

Answer 1

var latitude = Model.Latitude;
var longitude =Model.Longitude;

应该是：

var latitude = @Html.Raw(Json.Encode(Model.Latitude));
var longitude = @Html.Raw(Model.Longitude));

还有这一点：

var title = "@Html.Encode(Model.Title)"
var address = "@Html.Encode(Model.Address)"

应该是：

var title = @Html.Raw(Json.Encode(Model.Title));
var address = @Html.Raw(Json.Encode(Model.Address));

Answer 2

试试这个：

var latitude = @Model.Latitude;
var longitude = @Model.Longitude;