results = results['results']['bindings'] Flask错误

Question

我尝试通过这个Sparql查询获得结果绑定。通过这个Sparql入口点：http://digitale.bncf.firenze.sbn.it/openrdf-workbench/repositories/NS_03_2014/query

我有一个错误："TypeError: query()接受至少2个参数(给定1个)

谢谢！

@app.route('/caricaArgomento/<type>', methods=['GET'])
def getArgomento(type):
    #sparql = SPARQLUpdateStore("http://digitale.bncf.firenze.sbn.it/openrdf-      workbench/repositories/NS_03_2014/query")
    sparql=SPARQLUpdateStore("http://digitale.bncf.firenze.sbn.it/openrdf-workbench/repositories/NS_03_2014/query")
    sparql.setQuery("""
    PREFIX dc:<http://purl.org/dc/elements/1.1/>
    PREFIX rdfs:<http://www.w3.org/2000/01/rdf-schema#>
    PREFIX nsogi:<http://prefix.cc/nsogi>
    PREFIX rdf:<http://www.w3.org/1999/02/22-rdf-syntax-ns#>
    PREFIX skos:<http://www.w3.org/2004/02/skos/core#>
    PREFIX dcterms:<http://purl.org/dc/terms/>
        SELECT ?risultato
        WHERE {
         ?item a skos:Concept .
         ?item skos:prefLabel ?risultato .
         filter regex(?risultato, """+type+""", "i")
        } ORDER BY  ?risultato
         """)

     #FILTER regex(str(?aConcept), "http://thes.bncf.firenze.sbn.it/", "i").}

    sparql.setReturnFormat(JSON)
    results = sparql.query().convert()
    results = results['results']['bindings']
    results = json.dumps(results)

return results

digitale.bncf.firenze.sbn.it digitale.bncf.firenze.sbn.it

Answer 1

查看相关的documentation sparql.query()...需要一个查询参数。

sparql=SPARQLUpdateStore("http://digitale.bncf.firenze.sbn.it/openrdf-workbench/repositories/NS_03_2014/query")

sparql.setReturnFormat(JSON)

query = """
    PREFIX dc:<http://purl.org/dc/elements/1.1/>
    PREFIX rdfs:<http://www.w3.org/2000/01/rdf-schema#>
    PREFIX nsogi:<http://prefix.cc/nsogi>
    PREFIX rdf:<http://www.w3.org/1999/02/22-rdf-syntax-ns#>
    PREFIX skos:<http://www.w3.org/2004/02/skos/core#>
    PREFIX dcterms:<http://purl.org/dc/terms/>
    SELECT ?risultato
    WHERE {
     ?item a skos:Concept .
     ?item skos:prefLabel ?risultato .
     filter regex(?risultato, """+type+""", "i")
    } ORDER BY  ?risultato
"""

results = sparql.query(query).convert()

我不知道sparql.setQuery(...)的用途是什么，但很明显它不是你想要的。

编辑：

看过源代码后，setQuery(...)实际上是供内部使用的(例如，编写子类的人)，而不是普通的api用户。它拉出查询表单并记录查询文本。query(...)在内部调用它。