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社区首页 >问答首页 >PHP会话在表单提交时结束

问PHP会话在表单提交时结束
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Stack Overflow用户
提问于 2014-03-02 18:46:29
回答 1查看 114关注 0票数 0

当我在一个页面上提交一个表单时,我遇到了一个问题,这导致会话结束,用户必须重新登录。我花了几个小时试着整理这件事,但什么也没做!这是表单所在页面的代码-

代码语言:javascript
复制
<?php
session_start(); /// initialize session
$title = 'Month Edit';
include("passwords.php");
$user_email = check_logged(1, $dbc);
?>

表单代码只是

passwords.php页面是

代码语言:javascript
复制
<?php
require ('ct_db.php');//This is the database info
$query = "SELECT * FROM users";
$result = mysqli_query ($dbc, $query);

while($check_row = mysqli_fetch_array($result, MYSQLI_ASSOC))
{
  $this_us = $check_row['user'];
  $this_ps = $check_row['pass'];
  $USERS[$this_us] = $this_ps;
}

function check_logged($page, $dbc)
{ 
     global $_SESSION, $USERS;
     if (!array_key_exists($_SESSION["logged"],$USERS))
      { 
        header("Location: login.php"); 
     }
     else
     {
        $this_user = $_SESSION["logged"];
        $query = "SELECT * FROM users WHERE user = '$this_user'";
        $result = mysqli_query ($dbc, $query);
        $row2 = mysqli_fetch_array($result, MYSQLI_ASSOC);
        $user_email = $row2['email'];
        $user_permission = $row2['permissions'];
        if($page == 3 && ($user_permission=="admin" || $user_permission=="user"))
        {
         header("Location: login.php"); 
        }
      else
      {
      if($page == 2 && $user_permission=="user")
      {
      header("Location: login.php"); 
      }
      else
      {
        echo '<div id="logged_in">';
        echo '<form action="login.php" method="post"><input type="hidden" name="ax" value="out"> '; 
        echo 'Logged in as <span style="color:blue">'.$_SESSION["logged"]."</span> ";
        echo 'email '.$user_email.' ';
        echo '<input type="submit" value="Logout" id="log_out"/></div><br>'; 
        return $user_email;
      }
    }
    }
}; 
?>

我还有一个登录页面,其中包括以下内容

代码语言:javascript
复制
<?php
session_start();
$title = 'login';
require ('ct_db.php');
$query = "SELECT * FROM users";
$result = @mysqli_query ($dbc, $query);

 while($check_row = mysqli_fetch_array($result, MYSQLI_ASSOC))
  {
  $this_us = $check_row['user'];
  $this_ps = $check_row['pass'];
  $USERS[$this_us] = $this_ps;
  }


function check_logged($page)
{ 
     global $_SESSION, $USERS; 
     if (!array_key_exists($_SESSION["logged"],$USERS))
      { 
        header("Location: login.php"); 
     }
     else
     {
        $this_user = $_SESSION["logged"];
        require ('ct_db.php');
        $query = "SELECT * FROM users WHERE user = '$this_user'";
        $result = mysqli_query ($dbc, $query);
        $row2 = mysqli_fetch_array($result, MYSQLI_ASSOC);
        $user_email = $row2['email'];
        $user_permission = $row2['permissions'];
        if($page == 3 && ($user_permission=="admin" || $user_permission=="user"))
        {
         header("Location: login.php"); 
        }
      else
      {
      if($page == 2 && $user_permission=="user")
      {
      header("Location: login.php");
      }
      else
      {
        echo '<div id="logged_in">';
        echo '<form action="login.php" method="post"><input type="hidden" name="ax" value="out"> '; 
        echo 'Logged in as <span style="color:blue">'.$_SESSION["logged"]."</span> ";
        echo 'email '.$user_email.' ';
        echo '<input type="submit" value="Logout" id="log_out"/>'; 
        return $user_email;
        }
        }
    }
}; 

require ('ct_db.php');
if ($_POST["ac"]=="log")
 { /// do after login form is submitted  
     if ($USERS[$_POST["username"]]==$_POST["password"]) /// check if submitted  username and password exist in $USERS array 
     { 
          $_SESSION["logged"]=$_POST["username"];
          $_SESSION["email"] = 'email address';
          echo 'email = '.$_SESSION["email"];
     } 
     else
     {
          echo 'Incorrect username/password. Please, try again.';
     };
};

if ($_POST["ax"]=="out")
 { /// do after login form is submitted
     if ($USERS[$_POST["username"]]==$_POST["password"]) /// check if submitted  username and password exist in $USERS array 
     {
          session_destroy();
          echo 'You are logged out';
          //header("Location: login.php");
          die;
     }
}; 

if (array_key_exists($_SESSION["logged"],$USERS)) //// check if user is logged or not  
{ 
     echo "You are logged in.";
     echo '<form action="login.php" method="post"><input type="hidden" name="ax" value="out"> '; 
     echo '<input type="submit" value="Logout" />'; 
     echo '</form>';
     header("Location: mainPage3.php"); 

      //// if user is logged show a message  
} 
else 
{ //// if not logged show login form 
    echo '<div id="login">';
    echo '<h1>Connectivity</h1>';
    echo 'Please login<br><br>';
    echo '<form action="login.php" method="post"><input type="hidden" name="ac" value="log"> '; 
    echo 'Username: <input type="text" name="username" id="username"/><br>'; 
    echo 'Password: <input type="password" name="password" id="password"/><br>'; 
    echo '<input type="submit" value="Login" />'; 
    echo '</form>'; 
    echo '</div><!--End login-->';
}; 
?>

在我尝试解决这个问题的过程中,我已经更改并添加了很多代码,我确信它会比实际情况更复杂。我可以在不注销的情况下使用站点从一个页面移动到另一个页面,并且可以刷新包含表单的页面。但是如果我按下submit,我就会返回到登录页面。我唯一能想到的可能是用户信息与站点信息在不同的数据库中,但我已经检查过了,以确保我有正确的代码。感谢您给予的任何帮助。

EN

回答 1

Stack Overflow用户

发布于 2014-03-02 20:07:39

我只能在您的代码中看到两种提交按钮,登录和注销(两次),并且两个表单都有action = login.php。

单击注销按钮时,将通过代码销毁会话。当已经登录的用户单击登录按钮(假设该按钮可见)时,它会将post中的值设置为空值,并且用户将被重定向到login.php页面,因为验证将抛出login == false。

我没有测试你的代码,但显然这似乎是问题所在。

票数 0
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页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/22126596

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