spyOn函数未按预期工作

Question

我的控制器做了类似下面的事情：

.controller('demo',function($scope,$state, $modal,$q, Resource1, Resource2) {

  function1(){
     var deferred = $q.defer();
     Resource1.get(function(result){
         $scope.player = result;
         deferred.resolve(promise);
     });
     return deferred.promise;
  }  

  function2() { /* similar to function1. It also returns a promise */ }

   $q.all(function1(),function2(),function(result){

   });

});

我迫使自己sofar...beyond这我是一种迷失。首先，我想知道我的初始化是否正确，其次，我想知道如何编写单元测试来测试function1()是否被调用，以及Resource1在那之后是否被调用。这就是我到目前为止所知道的：

describe('demo',function(){


  beforeEach(function(){
      $rootScope = $injector.get('$rootScope');
      $controller = $injector.get('$controller');
      $httpBackend = $injector.get('$httpBackend');
      q = $injector.get('$q');
      state = $injector.get('$state');
   });

  createController = function(){
      return $controller('demo',{
        $scope: $rootScope.$new(),
        $state: state,
        $modal: sinon.stub({}),
        $q: q,
        Resource1: mockResource1, /*how and where to initialize mock Resources */
        Resource2: mockResource2, 

      });

    } //end beforeEach

   it('should check that func1 was called',function(){
          spyOn(this,'function1');
          var controller = createController();
          expect(this.function1).toHaveBeenCalled();
    });

   it('should check that Resource1.get as called',function(){
          //  how to formulate the test here 
    });

});

Answer 1

我认为function1是一个存在于控制器作用域内的函数。你不能“触摸”它，所以你不能“监视”它。